Dear Macella,
As in previous post, to ensure the low spin of Co2+, the BS was set as following.
According to my understanding, this means add 4 elelctrons to the alpha spin of Co 3d orbital, and 1 electron to the beta spin of Co 3d orbital. Am I correct? As in the CP2K manual, the total electrons with alpha spin should be divided by 2, so finally, (7+4)/2=5.5 electrons with alpha spin state in Co 3d orbital, and 4 electron woth beta spin in Co 3d orbital. Correct?
So, what is the meaning of 5.5 elelctrons in 3d orbital with alpha spin? I am confused. Thank you very much.
&BS
&ALPHA
NEL +4 -2
L 2 0
N 3 4
&END ALPHA
&BETA
NEL +1 -2
L 2 0
N 3 4
&END BETA
&END BS
Regards,
Jiapeng
-------- 原始邮件 --------
主题:Re: 回复:[CP2K:12654] Re: Spin Initialization
发件人:Marcella Iannuzzi
收件人:cp2k
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