Humid air Enthalpy depending on water's latent heat

18 views
Skip to first unread message

Pierre Richard

unread,
Sep 30, 2024, 11:49:49 AM9/30/24
to coolprop-users

Hello,

A colleague of mine recently pointed out that the calculation of humid air enthalpy is based on the latent heat of water at a specific point (2500.8 kJ/kg). I suppose this is fine when you stay around room temperature, but we work on industrial drying processes and often deal with high temperatures and high humidities in our calculations.

According to him, this can lead to a difference of up to 15% in the results.

I don't have the mathematical background to fully understand this.

My question then is : does COOLPROP take into account the variation in the latent heat of water ? Or is my colleague right, and I need to manually redo my enthalpy calculations?

Thank you for you help.

Ian Bell

unread,
Oct 9, 2024, 8:18:00 PM10/9/24
to coolpro...@googlegroups.com
I'm not sure about this. I believe that the enthalpy of water is handled correctly by the model, but to be sure, you should check out the report upon which the humid air mixture model is based. Without more detail it is hard to know for sure. Can you provide some numerical values from your calculations and what you expect them to be?

--
You received this message because you are subscribed to the Google Groups "coolprop-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email to coolprop-user...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/coolprop-users/d228e2b5-f502-45fa-a5e1-83966182198cn%40googlegroups.com.
Reply all
Reply to author
Forward
0 new messages