string picker width is 0

[howud...@gmail.com]

the string picker is showing with no width, so the items can't be chosen?

     Picker picker = new Picker();

    picker.setStrings("", "String 1", "String 2");

    TableLayout layout = new TableLayout(5,3);

        Container cnt1 = new Container(layout);

        cnt1.add(layout.createConstraint().widthPercentage(20), new Label());

        cnt1.add(layout.createConstraint().widthPercentage(40), new Label());

        cnt1.add(layout.createConstraint().widthPercentage(40), new Label());

    cnt1.add(layout.createConstraint().horizontalSpan(1), new Label("Last:"));

    cnt1.add(layout.createConstraint().horizontalSpan(1), new TextField());

    cnt1.add(layout.createConstraint().horizontalSpan(1),picker);

result:

[Shai Almog]

Odd that it would do that. Use setRenderingPrototype("XXXXXXXXXXXX") to determine the width for the picker.

Notice that on device this should map to the native picker for most cases and it will behave differently.

[howud...@gmail.com]

ok, that sort of worked.  I guess I'll have to go through all the entries, find the longest one and use that.   bummer :(

[Shai Almog]

Just use a longer value than you are ever likely to have. FYI I've set a default prototype to the picker which makes sense so this should not behave like that in the coming update.

[howud...@gmail.com]

thanks, will look forward to the update, for now I do:

    protected void setStrings (Picker picker, String[] strs) {

    picker.setStrings(strs);

    String sLongest = "";

    for (String s : strs)

    if (s.length() > sLongest.length())

    sLongest = s;

    picker.setRenderingPrototype(sLongest);

    }