Need Grep help to get first digit (or letter) in each row

[Howard]

Using the input data below and using Grep, I need either the first digit  or letter extracted from each row (just one per row), so the output looks like what is shown below. Though the output is displayed here in horizontal format, I need the actual output in vertical format without any commas.

Howard

Output

9, 3, D, 6, 8, 5, 3, 9, 5, 2, 7, 4, 3, D, 8, 7

Input data:

*9/HD
*3D/5
*D1/H97
*69/8HD
*87/HD
57983/H
*3
*97D/8H
*5D/H
*2/D3H
*7H/8
*4/H
*3/D5
*D7/9
*84/H
7DH/9

[Tom Robinson]

^[^a-z0-9]*(.).*$

^ at beginning of line
[^a-z0-9] look for anything which isn’t a-z 0-9
* 0 or more times
(.) any single character (i.e. a-z 0-9), and ‘capture’ it for replacement pattern
★ any characters
$ end of line

Replace with

\1

Cheers

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[Christopher Waterman]

Hello Howard,

Find: ^[^0-9A-Z]?([0-9A-Z]).*

Replace: \1

— Chris(topher)?

[Howard]

Thanks Tom and Christopher.

Howard