Run a task based on variable defined or not

[Neetu]

Hi Guys

Can some one here help me on how to run a task if a variable is undefined.

I want to check if a variable exists or not and register that .

If Variable exists I want to run a task. 

Has any one successfully done this ?

[Sosys]

Hi,

have you tried to use "undefined" in the when statement  ?

===

when: yourvarname is undefined

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[Neetu]

Yes, I have used that. 

But my task is being skipped , even when the variable is defined

Here is what I am doing

- name: Check the variable value which is in dictionary

  debug:

    var: certs[a][b][c][d]['certs']

  register: results

- debug:

    var: results

- name: "set the value"

  set_fact:

    s_cert: ["{{ item }}", ]

  with_items:

    - "{{ certs[a][b][c][d]['certs'] }}"

  when: results  is undefined

so , when I run it, in both cases where variable has some value and variable is undefined, the task is being skipped

On Thursday, August 16, 2018 at 11:16:02 PM UTC-7, Benny Kusman wrote:

Hi,

have you tried to use "undefined" in the when statement  ?

===

when: yourvarname is undefined

On Fri, Aug 17, 2018 at 5:17 AM, Neetu <arumalla...@gmail.com> wrote:

Hi Guys

Can some one here help me on how to run a task if a variable is undefined.

I want to check if a variable exists or not and register that .

If Variable exists I want to run a task. 

Has any one successfully done this ?

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[Kai Stian Olstad]

On 17.08.2018 09:39, Neetu wrote:
> Yes, I have used that.

I have know idea what you are trying to do, but you should probably try
to explain in more detail and maybe show the output.

> But my task is being skipped , even when the variable is defined
>
> Here is what I am doing
> - name: Check the variable value which is in dictionary
> debug:
> var: certs[a][b][c][d]['certs']
> register: results

The variable result will always have a value...

> - debug:
> var: results
>
> - name: "set the value"
> set_fact:
> s_cert: ["{{ item }}", ]
> with_items:
> - "{{ certs[a][b][c][d]['certs'] }}"
> when: results is undefined

...so the variable result will always be defined so this task will never
run.

You probably just want to do this, delete the when and just use

{{ certs[a][b][c][d]['certs'] | default([]) }}

--
Kai Stian Olstad

[Neetu]

Sorry for not mentioning it clearly.

I got it fixed.

My issue was , I am taking the values of a.b,c,d dynamically.

so when I am checking for certs[a][b][c][d]['certs'] , it will check until ['certs']., last of the nested dict

My variable is 

certs:

  host1:

    host_type:

       host_name:

         host_flavor:

            certs:

               a: 1

               b:2

  host2:

    host_type:

       host_name:

         host_flavor:

            certs:

               a: 1

               b:2

so, when host3 doesn't have entry, I wanted it to skip the task  that I am running 

so, when using { certs[a][b][c][d]['certs'] | default([]) }} }

it errors out saying type 'dict' has no value u 'host3'

Instead of checking for { certs[a][b][c][d]['certs'] | default([]) }} }, Now I am doing 

{ certs[a] | default({})} --- > which solves my purpose.

when host3 is not present,it will skip the task

Thanks .