Replace indented string in file

[Tony]

I am trying to replace a specific part of an indented string, but I cannot get it working with lineinfile/replace modules for some reason.

What I would like:

before:        Substitute "s~(src|href)=('|\")/((?!version).*)~$1=$2/version//$3~i"

after:            Substitute "s~(src|href)=('|\")/((?!version).*)~$1=$2/9.1.2.3/$3~i"

Anyone help me out with this one please?

Cheers!

[Dick Visser]

Are those actual entire lines of content?

Because they contain regex patterns. 

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[Tony]

Hey, 

Are those actual entire lines of content?

Yes, they are the enter lines of the content. It is part of an application configuration file.

Because they contain regex patterns. 

Yes and I think this is why I cant get it working

Any pointers would be great, I just need to insert a replace "version" with a version number i.e. 9.1.2.3

[Dick Visser]

I think you misunderstood me.

Are those lines you put there the same as in your source file?

Because I think they're not. 

Instead of posting what appear to be randomly selected lines of a playbook:

* post the actual playbook/task that you have

* post a snippet of the real file content that you want to change

To view this discussion on the web visit https://groups.google.com/d/msgid/ansible-project/9420d0e1-4d34-4bb2-b61f-6820dbaef0a3n%40googlegroups.com.

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Dick Visser
Trust & Identity Service Operations Manager
GÉANT

[Tony]

I have a file called "bla.conf" which contains this indented line Substitute "s~(src|href)=('|\")/((?!version).*)~$1=$2/version//$3~i"

I want to change the indented line from bla.conf to Substitute "s~(src|href)=('|\")/((?!version).*)~$1=$2/NEWVERSIONHERE//$3~i"  

[Dick Visser]

Ah OK.

In such cases it is very hard to get the escaping right by hand, so what I usually do is use a helper task using regex_escape.

This lets ansible to the escaping for you. Once you have that escaped regex, the only thing you need to do, is to add parenthesis:

---

- hosts: localhost

  connection: local

  gather_facts: no

  vars:

    path: /tmp/out.txt

    original_line: Substitute "s~(src|href)=('|\")/((?!version).*)~$1=$2/version//$3~i"

    new_version: v3.78.1

  tasks:

    # Helper task to escape the entire line

    - debug: var=original_line|regex_escape

    - replace:

        path: "{{ path }}"

        # This regexp has the verbatim output of the previous debug task, it is used to confirm a match

        #regexp: Substitute\ "s\~\(src\|href\)=\('\|\\"\)/\(\(\?!version\)\.\*\)\~\$1=\$2/version//\$3\~i"$

        # This is the same, but with the part before and after "version" in parenthesis

        regexp: ^(Substitute\ "s\~\(src\|href\)=\('\|\\"\)/\(\(\?!version\)\.\*\)\~\$1=\$2/)version(//\$3\~i")$

        replace: '\1{{ new_version }}\2'

~                                                                                                                   

~                                                                                                                   

regex_replace2.yml                                                                                18,18          All

"regex_replace2.yml" 27L, 807B written

Of course this is done using the literal string "version" - so you'd have to adjust that if you want to match something else.

Dick

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