Using LabelService to get LabelID by label name

[some...@gmail.com]

How to Get Label Id by Label name?

        campaign_service = adwords_client.GetService('LabelService', version='v201710')

        selector = {
            'fields': ['id', 'name', 'status'],
            'predicates': [{
                'field': 'LabelId',
                'operator': 'EQUALS',
                'values': [labelText]
                }
                ],
            }

        result = campaign_service.get(selector)

I am getting this error:

[SelectorError.INVALID_FIELD_NAME @ serviceSelector; trigger:'id', SelectorError.INVALID_FIELD_NAME @ serviceSelector; trigger:'name', SelectorError.INVALID_FIELD_NAME @ serviceSelector; trigger:'status', SelectorError.INVALID_PREDICATE_VALUE @ serviceSelector; trigger:'TestLabel 2017.56']

I was following this documentation

https://developers.google.com/adwords/api/docs/reference/v201710/LabelService.Label

but it did not help much. Does anyone did it before and figure out the solution?

[Vincent Racaza (AdWords API Team)]

Hi Someo,

According to the documentation that you linked, the fields can be selected using "LabelId", "LabelName" and "LabelStatus" as field names. Please use these field names instead in your selector:

selector = {
    'fields': ['LabelId', 'LabelName', 'LabelStatus'],

Let me know if this helps.

Thanks,

Vincent

AdWords API Team