Get "Cost" without interactions that can’t lead to conversions in AdWords API

[Tiana S.]

Hi guys,

As you don't provide a predefined metric to request "Conv. value / cost" in the Reporting API, we're calculating it ourselves by doing `Total Conv. Value / cost`. 

We've been using this calculation for a while, however, since recently we are noticing some discrepancies with the interface in some cases. Checking the definition again, we found that it now includes the following: 

The cost in this metric excludes interactions that can’t lead to conversions, such as those that happen when you aren’t using conversion tracking.

Is there anyway we can fetch that cost, so excluding the interactions that can't lead to conversions, so we can calculate a correct "Conv. value / cost"?
And if not, are there by any chance plans to add "Conv. value / cost" and "Conv. value / click" to the API?

Thanks,

Tiana

[Bharani Cherukuri (AdWords API Team)]

Hello Tiana, 

Could you please point me to the specific document that you're referring to or the UI screenshot, so I can take a look? The fields Conv. value / cost and Conv. value / click are currently not supported through the API. I have shared your interest with the team. Please keep an eye on our blog for more updates regarding this feature. 

Thanks,

Bharani, AdWords API Team

[Tiana S.]

Hi Bharani,

Thanks for your reply! I sent a confidential reply with a screenshot. :)

Best,

Tiana

[Bharani Cherukuri (AdWords API Team)]

Hello Tiana, 

Thank you for sharing the screenshot. The conv. value/ cost is currently not a supported field through the API. It is also not possible to pull the cost that excludes interactions which did not lead to conversions. You could post your concern on the Advertisers Community forum, so the product experts will be able to take a look and assist you as to how they calculate this value. 

Regards,
Bharani, AdWords API Team

On Thursday, August 9, 2018 at 7:41:23 AM UTC-4, Tiana S. wrote:

[Tiana S.]

Awesome! I'll ask them for more details on the calculation then. :) Thanks for pointing me in the right direction!

Best,

Tiana