Mirror position
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Eric Thivierge
Mar 20, 2012, 7:11:41 AM3/20/12
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Hey all,
Wondering how I can mirror a transform's position without having to decompose the matrix into SRT and even further into the translation vector to multiply the X position value by -1. Not worried about converting space at this state so we can assume I'm working in the object's local transform space.
Am I stuck digging down into the matrix?
Simon Anderson
Mar 20, 2012, 7:56:55 AM3/20/12
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if i understand correctly you are wanting to take the matrix and perform an equation directly on the matrix that mirrors the position? a matrix multiplication that flips it right?
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Eric Thivierge [ethiv...@gmail.com]
Sent: Tuesday, March 20, 2012 1:11 PM
To: soft...@listproc.autodesk.com
Subject: Mirror position
Sent: Tuesday, March 20, 2012 1:11 PM
To: soft...@listproc.autodesk.com
Subject: Mirror position
Eric Thivierge
Mar 20, 2012, 8:02:53 AM3/20/12
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Yeah. I've tried multiplying a source matrix in ICE by one that has a negative X position value but its not working. I'm still working on my matrix math concepts. :\
Dan Yargici
Mar 20, 2012, 8:08:15 AM3/20/12
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Simon Anderson
Mar 20, 2012, 8:17:38 AM3/20/12
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I havent done matricies in a while but i think if you multiple your matricy by
[1,0,0,0]
[0,1,0,0]
[0,0,1,0]
[0,0,0,1]
it will inverse your matrix
[1,0,0,0]
[0,1,0,0]
[0,0,1,0]
[0,0,0,1]
it will inverse your matrix
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Dan Yargici [danya...@gmail.com]
Sent: Tuesday, March 20, 2012 2:08 PM
To: soft...@listproc.autodesk.com
Subject: Re: Mirror position
Sent: Tuesday, March 20, 2012 2:08 PM
To: soft...@listproc.autodesk.com
Subject: Re: Mirror position
Simon Anderson
Mar 20, 2012, 8:19:17 AM3/20/12
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woops that was wrong LOL
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: Simon Anderson
Sent: Tuesday, March 20, 2012 2:17 PM
To: soft...@listproc.autodesk.com
Subject: RE: Mirror position
Sent: Tuesday, March 20, 2012 2:17 PM
To: soft...@listproc.autodesk.com
Subject: RE: Mirror position
Eric Thivierge
Mar 20, 2012, 8:19:23 AM3/20/12
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Yeah I understand how to read them and set them but the math part of operations on matrices is what I'm probably struggling with. Guess I'm going to have to hit up kahn academy.
Simon Anderson
Mar 20, 2012, 8:20:36 AM3/20/12
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[-1,0,0,0]
[0,-1,0,0]
[0,0,-1,0]
[0,0,0,1]
[0,-1,0,0]
[0,0,-1,0]
[0,0,0,1]
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: Simon Anderson
Sent: Tuesday, March 20, 2012 2:17 PM
To: soft...@listproc.autodesk.com
Subject: RE: Mirror position
Sent: Tuesday, March 20, 2012 2:17 PM
To: soft...@listproc.autodesk.com
Subject: RE: Mirror position
Eric Thivierge
Mar 20, 2012, 8:23:19 AM3/20/12
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haha I tried multiplying it by:
[1,0,0,0]
[0,1,0,0]
[0,0,1,0]
[-1,0,0,1]
[0,1,0,0]
[0,0,1,0]
[-1,0,0,1]
hoping the -1 in the translation would do it but no dice. I don't want to mirror the whole transform just the position of the matrix
Simon Anderson
Mar 20, 2012, 8:28:56 AM3/20/12
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thats a scale inverse, but im guessing you want to do a rotation and position inverse. wheres my maths book when i need it XD
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Eric Thivierge [ethiv...@gmail.com]
Sent: Tuesday, March 20, 2012 2:23 PM
Peter Agg
Mar 20, 2012, 8:29:56 AM3/20/12
to soft...@listproc.autodesk.com
If I'm getting what you mean correctly...
If you have a vector (5, 2, 5), then multiply it by
If you have a vector (5, 2, 5), then multiply it by
[-1,0,0,0]
[0,1,0,0]
[0,0,1,0]
[0,0,0,1]
You'll get (-5, 2, 5), inverting it just in the x axis. The second and third rows would do y and z respectively.
[0,1,0,0]
[0,0,1,0]
[0,0,0,1]
You'll get (-5, 2, 5), inverting it just in the x axis. The second and third rows would do y and z respectively.
Edy Susanto
Mar 20, 2012, 8:33:40 AM3/20/12
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not answering your first question, but multiplying 2 matrix basically
transform with the second matrix in the first matrix space and the
result is the "global" version of the second matrix.
transform with the second matrix in the first matrix space and the
result is the "global" version of the second matrix.
-edy
On 3/20/2012 11:02 PM, Eric Thivierge wrote:
> Yeah. I've tried multiplying a source matrix in ICE by one that has a
> negative X position value but its not working. I'm still working on my
> matrix math concepts. :\
>
> --------------------------------------------
> Eric Thivierge
> http://www.ethivierge.com
>
>
> On Tue, Mar 20, 2012 at 10:56 PM, Simon Anderson
> <Simon.A...@triggerfish.co.za
> <mailto:Simon.A...@triggerfish.co.za>> wrote:
>
> if i understand correctly you are wanting to take the matrix and
> perform an equation directly on the matrix that mirrors the
> position? a matrix multiplication that flips it right?
>
> Simon Ben Anderson
> Lead Developer + Lead Rigger
> Triggerfish Studios
> http://www.triggerfish.co.za
>
> ------------------------------------------------------------------------
> *From:* softimag...@listproc.autodesk.com
> <mailto:softimag...@listproc.autodesk.com>
> [softimag...@listproc.autodesk.com
> <mailto:softimag...@listproc.autodesk.com>] on behalf of Eric
> Thivierge [ethiv...@gmail.com <mailto:ethiv...@gmail.com>]
> *Sent:* Tuesday, March 20, 2012 1:11 PM
> *To:* soft...@listproc.autodesk.com
> <mailto:soft...@listproc.autodesk.com>
> *Subject:* Mirror position
Simon Anderson
Mar 20, 2012, 8:36:07 AM3/20/12
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ahoy man, not sure if this will help, as you probabily have taken a look at this already but just incase you havent
http://en.wikipedia.org/wiki/Matrix_%28mathematics%29
Ill see if i can rattle my brains into action :)
http://en.wikipedia.org/wiki/Matrix_%28mathematics%29
Ill see if i can rattle my brains into action :)
From: Simon Anderson
Sent: Tuesday, March 20, 2012 2:28 PM
Sent: Tuesday, March 20, 2012 2:28 PM
Eric Thivierge
Mar 20, 2012, 8:43:13 AM3/20/12
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Thanks Simon will have a read through,
Basically I want to do this without all the conversion and only using matrices. If its not possible so be it. Just shooting it out there to see if it was possible. :\
Peter Agg
Mar 20, 2012, 8:50:23 AM3/20/12
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Yep, if you get the null1 global kine, multiply it by the matrix I posted above then it'll mirror in X just fine. Just tested myself.
I'd post a picture but, well, it's 3 nodes and doesn't show much. :)
I'd post a picture but, well, it's 3 nodes and doesn't show much. :)
Michal Doniec
Mar 20, 2012, 8:51:34 AM3/20/12
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http://ndu2009algebra.blogspot.co.uk/2011/05/mirroring-point-on-3d-plane.html
That should help, matrix version is at the bottom.
I have ICE version, but it too big to fit on the screen, not sure if you can decipher it.--
----------
Michal
http://uk.linkedin.com/in/mdoniec
That should help, matrix version is at the bottom.
I have ICE version, but it too big to fit on the screen, not sure if you can decipher it.
----------
Michal
http://uk.linkedin.com/in/mdoniec
Simon Anderson
Mar 20, 2012, 8:52:14 AM3/20/12
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hey, so i bashed around some numbers, not sure if its what will work but have a try
look at attached it seems to work
look at attached it seems to work
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Eric Thivierge [ethiv...@gmail.com]
Sent: Tuesday, March 20, 2012 2:43 PM
Simon Anderson
Mar 20, 2012, 8:57:35 AM3/20/12
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Should of explained the image a bit better:
Have two nulls both rotated, and parented under the scene root,
Original null called 'null' which one can move and rotate, then the inverse ICE driven null called 'Mover'
just did a test i have inverted the motion of the forward X axis, so just change it to
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[,0,0,1]
and that should do the job
Have two nulls both rotated, and parented under the scene root,
Original null called 'null' which one can move and rotate, then the inverse ICE driven null called 'Mover'
just did a test i have inverted the motion of the forward X axis, so just change it to
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[,0,0,1]
and that should do the job
Simon Anderson
Mar 20, 2012, 9:00:40 AM3/20/12
to soft...@listproc.autodesk.com
missed a 0, sorry about all the mistakes in my emails, still at work and its my last week so
smashing out the bugs here and trying to setup future plans, and helping out UBER multitasking lol
let me know if this does the job or if it doesn't ill try something else
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[0,0,0,1]
let me know if this does the job or if it doesn't ill try something else
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[0,0,0,1]
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: Simon Anderson
Sent: Tuesday, March 20, 2012 2:57 PM
Sent: Tuesday, March 20, 2012 2:57 PM
Alok Gandhi
Mar 20, 2012, 9:23:08 AM3/20/12
to soft...@listproc.autodesk.com
Just decompose into vectors and invert the first vector from your
transform matrix and pack again
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Simon Anderson
Mar 20, 2012, 9:32:41 AM3/20/12
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Mirror Matrix:
Input Matrix A (original Local or Global Kinematics), Multiple by a 4D Matrix and have the Matrix setup to be
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[0,0,0,1]
This will mirror rotations, scale, and location.
Input Matrix A (original Local or Global Kinematics), Multiple by a 4D Matrix and have the Matrix setup to be
[1,0,0,0]
[0,1,0,0]
[0,0,-1,0]
[0,0,0,1]
This will mirror rotations, scale, and location.
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Alok Gandhi [alok....@modusfx.com]
Sent: Tuesday, March 20, 2012 3:23 PM
Sent: Tuesday, March 20, 2012 3:23 PM
Simon Anderson
Mar 20, 2012, 10:55:08 AM3/20/12
to soft...@listproc.autodesk.com
Thought I would create a nice explanation quickly, as I realised my previouse example didn't take into account parented objects that need to be driven.
any questions just let me know
any questions just let me know
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Simon Anderson [Simon.A...@triggerfish.co.za]
Sent: Tuesday, March 20, 2012 3:32 PM
Sent: Tuesday, March 20, 2012 3:32 PM
Sandy Sutherland
Mar 20, 2012, 11:06:25 AM3/20/12
to soft...@listproc.autodesk.com
Cough..............get back to work Simon.................. ;^)
[giggles on an afternoon off]
S.
[giggles on an afternoon off]
S.
_____________________________
Sandy Sutherland
Technical Supervisor
sandy.su...@triggerfish.co.za
_____________________________
Sandy Sutherland
Technical Supervisor
sandy.su...@triggerfish.co.za
_____________________________
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Simon Anderson [Simon.A...@triggerfish.co.za]
Sent: 20 March 2012 16:55
Simon Anderson
Mar 20, 2012, 11:14:51 AM3/20/12
to soft...@listproc.autodesk.com
A YOU! stop working and enjoy your afternoon off HAHAHA!! :D
Simon Ben Anderson Lead Developer + Lead Rigger Triggerfish Studios http://www.triggerfish.co.za
From: softimag...@listproc.autodesk.com [softimag...@listproc.autodesk.com] on behalf of Sandy Sutherland [Sandy.Su...@triggerfish.co.za]
Sent: Tuesday, March 20, 2012 5:06 PM
Sent: Tuesday, March 20, 2012 5:06 PM
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