How to set the default for a color parameter in a shaderdef?

[Stefano Jannuzzo]

Hi folks.

In a shaderdef define function, I can create a color param and set its default value to a mid gray by   

paramOptions = XSIFactory.CreateShaderParamDefOptions();

paramOptions.SetDefaultValue(0.5);

params.AddParamDef("color", siShaderDataTypeColor3, paramOptions);

Any idea how to set each channel independently?

Thanks. Stefano

[Vincent Ullmann]

Hi,

i have something like this in my Shader-Definitions:

inputParameterOptions.SetDefaultValue([1, 1, 1])

[Vladimir Jankijevic]

like this: paramOptions.SetDefaultValue( [0.5, 0.3, 0.2] )

[Vincent Ullmann]

Becouse it partly fits on this Topic:

Does anyone know how to set the Viewport-Mapping in a Python-ShaderDefinition?

In a SPDL-File you can set a it via
ui "mapping"

Is there a similar function for Python?

[Nicolas Burtnyk]

In C++ you do this to set the diffuse ui mapping (should be simple to port this to python):

diffuseParamDef.GetAttributes().Set(L"{8C80DEF3-1064-11d3-B0B7-00A0C982A112}",  L"{3515CC72-082C-11D0-91DE-00A024C78EE3}");

The GUID "{8C80DEF3-1064-11d3-B0B7-00A0C982A112}" means "ui mapping".

The GUID "{3515CC72-082C-11D0-91DE-00A024C78EE3}" is the XSI GUID for diffuse.

GUIDs for other shader parameters (like spec etc..) can be found by looking at the ui mapping lines in material-phong.spdl.

-Nicolas

[Stefano Jannuzzo]

Thanks Vincent, Vladimir. Is this in python? It still doesn't work in jscript.

[Vincent Ullmann]

"Is this in python?" == True

[Stefano Jannuzzo]

I found the way in jscript after reading this

var paramDef = params.AddParamDef("scattering_color", siShaderDataTypeColor3, paramOptions);   

var subParamDef = paramDef.SubParamDefs;

subParamDef.GetParamDefByName("red").DefaultValue = 0.2;

subParamDef.GetParamDefByName("green").DefaultValue = 0.4;

subParamDef.GetParamDefByName("blue").DefaultValue = 0.6;