whatever's solution skips over tiddlers that have any of the 'noisy'
tags. However, what you want to do is still output information about
the tiddlers that have those tags while simply omitting the noisy tags
from the display. To do this, you need to modify the
"getSortedTagsText(tiddler)" function, so that the noisy tags are not
included in the resulting 'tags text'.
Replace this:
for (var i = 0; i < tags.length;i++) {
result += tags[i]+ " ";
}
with this:
for (var i = 0; i < tags.length;i++) {
if (!["noise1","noise2"].contains(tags[i])) result += tags[i]+ " ";
}
enjoy,
-e
Eric Shulman
TiddlyTools / ELS Design Studios
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