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The power of Riedt's constant Y = 5022635

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Peter Riedt

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Jan 16, 2018, 10:40:00 PM1/16/18
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The power of Riedt's constant Y = 5022635

If two of vm, rm and opy of any object orbiting the sun are known the missing third one
can be calculated by the formulas
rm=Y*vm*opy
vm=rm/Y/opy
opy=rm/vm/Y
These elements of the 9 major planets are given below as an example:

Y vm opy rm=Y*vm*opy
MER 5,022,635 47872 0.2408416 57,909,231,029
VEN 5,022,635 35021 0.6151856 108,209,525,401
EAR 5,022,635 29785 0.9999988 149,598,319,494
MAR 5,022,635 24131 1.8807278 227,943,771,564
JUP 5,022,635 13056 11.8693454 778,342,761,465
SAT 5,022,635 9644 29.4548244 1,426,714,892,866
URA 5,022,635 6799 84.0627938 2,870,633,540,862
NEP 5,022,635 5432 164.8713207 4,498,393,012,162
PLU 5,022,635 4738 248.2214844 5,906,438,090,764

rm Y opy vm=rm/Y/opy
MER 57,909,231,029 5,022,635 0.2408416 47872
VEN 108,209,525,401 5,022,635 0.6151856 35021
EAR 149,598,319,494 5,022,635 0.9999988 29785
MAR 227,943,771,564 5,022,635 1.8807278 24131
JUP 778,342,761,465 5,022,635 11.8693454 13056
SAT 1,426,714,892,866 5,022,635 29.4548244 9644
URA 2,870,633,540,862 5,022,635 84.0627938 6799
NEP 4,498,393,012,162 5,022,635 164.8713207 5432
PLU 5,906,438,090,764 5,022,635 248.2214844 4738

rm vm Y opy=rm/vm/Y
MER 57,909,231,029 47872 5,022,635 0.2408416322
VEN 108,209,525,401 35021 5,022,635 0.6151856070
EAR 149,598,319,494 29785 5,022,635 0.9999988008
MAR 227,943,771,564 24131 5,022,635 1.8807277596
JUP 778,342,761,465 13056 5,022,635 11.8693454242
SAT 1,426,714,892,866 9644 5,022,635 29.4548244442
URA 2,870,633,540,862 6799 5,022,635 84.0627938052
NEP 4,498,393,012,162 5432 5,022,635 164.8713206889
PLU 5,906,438,090,764 4738 5,022,635 248.2214843718

Libor 'Poutnik' Stříž

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Jan 17, 2018, 1:54:17 AM1/17/18
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Dne 17/01/2018 v 04:39 Peter Riedt napsal(a):
> The power of Riedt's constant Y = 5022635
>
> If two of vm, rm and opy of any object orbiting the sun are known the missing third one
> can be calculated by the formulas
> rm=Y*vm*opy
> vm=rm/Y/opy
> opy=rm/vm/Y

You rediscover the America.

> Y vm opy rm=Y*vm*opy
> [...]
> PLU 5,022,635 4738 248.2214844 5,906,438,090,764

"Nothing is better manifestation of ignorance in science
then an untamed precision of scientific calculations"

( A recalled title quote of unknown author
in a textbook of physical chemistry)

--
Poutnik ( The Pilgrim, Der Wanderer )

A wise man guards words he says,
as they say about him more,
than he says about the subject.

Peter Riedt

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Jan 17, 2018, 2:45:51 AM1/17/18
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I am not concerned about precision it is irrelevant in this context. What is relevant is the ability to calcuate missing orbital elements of any solar object with my constant. You and Bod keep harping about precision because you have nothing else to criticise. I'll try to keep throwing this bone to you to keep you happy.

Libor 'Poutnik' Stříž

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Jan 17, 2018, 2:54:12 AM1/17/18
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Dne 17/01/2018 v 08:45 Peter Riedt napsal(a):
> On Wednesday, January 17, 2018 at 2:54:17 PM UTC+8, Libor 'Poutnik' Stříž wrote:
>> Dne 17/01/2018 v 04:39 Peter Riedt napsal(a):
>>> The power of Riedt's constant Y = 5022635
>>>
>>> If two of vm, rm and opy of any object orbiting the sun are known the missing third one
>>> can be calculated by the formulas
>>> rm=Y*vm*opy
>>> vm=rm/Y/opy
>>> opy=rm/vm/Y
>>
>> You rediscover the America.
>>
>>> Y vm opy rm=Y*vm*opy
>>> [...]
>>> PLU 5,022,635 4738 248.2214844 5,906,438,090,764
>>
>> "Nothing is better manifestation of ignorance in science
>> then an untamed precision of scientific calculations"
>>
>> ( A recalled title quote of unknown author
>> in a textbook of physical chemistry)
>
> I am not concerned about precision it is irrelevant in this context. What is relevant is the ability to calcuate missing orbital elements of any solar object with my constant. You and Bod keep harping about precision because you have nothing else to criticise. I'll try to keep throwing this bone to you to keep you happy.

Your just rediscover the consequences of the laws known for centuries.

The result precision limited to the valid digits
it the first law of numerical processing of real data.

Well, near everything you write is very easy to criticize.
It becomes boring.

Libor 'Poutnik' Stříž

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Jan 17, 2018, 3:01:28 AM1/17/18
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Dne 17/01/2018 v 08:45 Peter Riedt napsal(a):

>
> I am not concerned about precision it is irrelevant in this context. What is relevant is the ability to calcuate missing orbital elements of any solar object with my constant. You and Bod keep harping about precision because you have nothing else to criticise. I'll try to keep throwing this bone to you to keep you happy.

Your constant is nothing more then a constant dependent on G and Ms,
expressed for units used for distances, speeds and periods.

This America was discovered centuries ago.
You bring nothing new.

Peter Riedt

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Jan 17, 2018, 5:50:28 PM1/17/18
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Y can calculate missing elements of planetary orbits. The solar system is full of these constants. Do you like to know more of them? I guess not.

Libor 'Poutnik' Stříž

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Jan 17, 2018, 6:17:26 PM1/17/18
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Dne 17/01/2018 v 23:50 Peter Riedt napsal(a):
> On Wednesday, January 17, 2018 at 4:01:28 PM UTC+8, Libor 'Poutnik' Stříž wrote:
>> Your constant is nothing more then a constant dependent on G and Ms,
>> expressed for units used for distances, speeds and periods.
>>
>> This America was discovered centuries ago.
>> You bring nothing new.
>>
>
> Y can calculate missing elements of planetary orbits. The solar system is full of these constants. Do you like to know more of them? I guess not.

Numbers do not know math, they cannot calculate anything.

Libor 'Poutnik' Stříž

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Jan 18, 2018, 1:33:29 AM1/18/18
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Dne 17/01/2018 v 04:39 Peter Riedt napsal(a):
> The power of Riedt's constant Y = 5022635
>
> If two of vm, rm and opy of any object orbiting the sun
> are known the missing third one
> can be calculated by the formulas

> rm=Y*vm*opy
> [...]

[km] = [s/year /(2pi)] * [km/s] * [year]

Your constant is an ordinary proportional constant
of relation of a circle radius in km,
the mean speed in km/s and the period in years.

If linearized, it is an indeed "powerful" formula

length = mean_speed * time


For an ellipse, it is not exact.

As it incorrectly supposes that
for the given period and semi major axis "a"
the orbit has the same mean speed
as a circular orbit would have, what is not true.

The various elliptical orbits with the same semi major axis
have the same period. But their mean speed nor the perigee speed
nor the apogee speed are NOT the same.

As the ellipse circumference is less than 2.pi.a.

But even this is not new for you,
as this was discussed with you before
ad nausea several times.

Peter Riedt

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Jan 18, 2018, 5:55:08 AM1/18/18
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Your comments are valid but irrelevant. What is relevant is Y allows to predict accurately missing elements of orbits of solar objects.

Libor 'Poutnik' Stříž

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Jan 18, 2018, 3:00:35 PM1/18/18
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Dne 18/01/2018 v 11:55 Peter Riedt napsal(a):
> On Thursday, January 18, 2018 at 2:33:29 PM UTC+8, Libor 'Poutnik' Stříž wrote:

>> [km] = [s/year /(2pi)] * [km/s] * [year]
>>
>> Your constant is an ordinary proportional constant
>> of relation of a circle radius in km,
>> the mean speed in km/s and the period in years.
>>
>> If linearized, it is an indeed "powerful" formula
>>
>> length = mean_speed * time
>>
>>
>> For an ellipse, it is not exact.
>>
>> As it incorrectly supposes that
>> for the given period and semi major axis "a"
>> the orbit has the same mean speed
>> as a circular orbit would have, what is not true.
>>
>> The various elliptical orbits with the same semi major axis
>> have the same period. But their mean speed nor the perigee speed
>> nor the apogee speed are NOT the same.
>>
>> As the ellipse circumference is less than 2.pi.a.
>>
>> But even this is not new for you,
>> as this was discussed with you before
>> ad nausea several times.
>>
> Your comments are valid but irrelevant. What is relevant is Y allows to predict accurately missing elements of orbits of solar objects.
>
No, it does not.
It fits only if you deliberately choose a particular speed value.

Peter Riedt

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Jan 18, 2018, 7:32:52 PM1/18/18
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All 9 major planets have a particular speed value which I used. If my vm values are wrong give me your's.

Libor 'Poutnik' Stříž

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Jan 19, 2018, 1:46:28 AM1/19/18
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Dne 19/01/2018 v 01:32 Peter Riedt napsal(a):
> On Friday, January 19, 2018 at 4:00:35 AM UTC+8, Libor 'Poutnik' Stříž wrote:
>>>
>> No, it does not.
>> It fits only if you deliberately choose a particular speed value.
>>
>
> All 9 major planets have a particular speed value which I used. If my vm values are wrong give me your's.

At a particular point on their orbits, yes.
What point have you chosen and why ?

As they have NO particular speed value,
their speed depends on their position on the orbit.

Aside of their immediate speed, apogee speed and perigee speed,
one can express their mean speed value,
that is given by ratio of the orbit circumference and the orbit period.

But for the given semi major axis and orbit period,
this mean speed is a function of eccentricity.

The ratio of this mean speed for the extreme cases
of e->1 and r->0 is 4/pi.

Where is this reflected in your X formula ??

The formula fits for the circular orbits only,
and only because of 2400 years old formulas
about circle circumference and v=L/t.

Libor 'Poutnik' Stříž

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Jan 19, 2018, 1:49:31 AM1/19/18
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Dne 19/01/2018 v 07:46 Libor 'Poutnik' Stříž napsal(a):
> But for the given semi major axis and orbit period,
> this mean speed is a function of eccentricity.
>
> The ratio of this mean speed for the extreme cases
> of e->1 and r->0 is 4/pi.
>
Errata: 2/pi // ( 4.r)/(2.pi.r)

Peter Riedt

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Jan 19, 2018, 3:56:06 AM1/19/18
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Yes but my X, Y and other constants have predictive powers.

Libor 'Poutnik' Stříž

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Jan 19, 2018, 3:41:23 PM1/19/18
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Dne 19/01/2018 v 09:56 Peter Riedt napsal(a):
>

> Yes but my X, Y and other constants have predictive powers.
>
X ( your "eccentricity" ) predicts nothing.

For Y, it can predict one of the following values from the other two:

a circle radius
a mean speed
a period

Something that old good Archimedes could do as well.

Peter Riedt

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Jan 20, 2018, 2:47:06 AM1/20/18
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Not with Y, he wouldn't have known it.

Libor 'Poutnik' Stříž

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Jan 20, 2018, 5:43:12 AM1/20/18
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Dne 20/01/2018 v 08:47 Peter Riedt napsal(a):
He did not need to know it.
It is just a different proportional constant
because of different unit set.

If you used the units consistently
( s and m/s, not years and m/s )
it would be 1/(2.pi).
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