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would it be possible to just have images of different spectra and have people compare the images they getting using the spectral workbench. I wan't to keep it as simple as possible for people. I won't have time to educate on any math at the workshop.also, is the peak height the identifier then?
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Perhaps another way to think about it is to consider the red channel an attenuator and normalize all channels based on the red channel amplitude at the laser frequency.
On 2014-08-11 12:56, Jeffrey Warren wrote:
Yagiz - do you think the laser peak height is going to be linearly
related to the rest of the curve? I worry that it's *so* bright that
it's clipping in the blue channel, as in this image from
http://spectralworkbench.org/analyze/spectrum/14919
Benjamin - I think the big issues we face right now are:
* getting enough light in so that the curve is closer to 25-75%
brightness, so it's not overwhelmed by noise
* adjusting the height of the curves to be comparable, by algorithm or
by visual comparison, which gets at Yagiz's distinction between area and
height, and my post about it:
http://publiclab.org/notes/warren/07-30-2014/equalizing-area-of-spectral-graphs-for-comparison
On Mon, Aug 11, 2014 at 11:50 AM, Benjamin Sugar
<goo...@skilfullycurled.org <mailto:google@skilfullycurled.org>> wrote:
would it be possible to just have images of different spectra and
have people compare the images they getting using the spectral
workbench. I wan't to keep it as simple as possible for people. I
won't have time to educate on any math at the workshop.
also, is the peak height the identifier then?
--
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ah, that's really clever, Dan! Yagiz, do you have a reference we can look at for why total peak height is more appropriate than area under curve? Thanks!
On Mon, Aug 11, 2014 at 2:16 PM, Dan Beavers <dan.b...@acm.org> wrote:
Perhaps another way to think about it is to consider the red channel an attenuator and normalize all channels based on the red channel amplitude at the laser frequency.
On 2014-08-11 12:56, Jeffrey Warren wrote:
Yagiz - do you think the laser peak height is going to be linearly
related to the rest of the curve? I worry that it's *so* bright that
it's clipping in the blue channel, as in this image from
http://spectralworkbench.org/analyze/spectrum/14919
Benjamin - I think the big issues we face right now are:
* getting enough light in so that the curve is closer to 25-75%
brightness, so it's not overwhelmed by noise
* adjusting the height of the curves to be comparable, by algorithm or
by visual comparison, which gets at Yagiz's distinction between area and
height, and my post about it:
http://publiclab.org/notes/warren/07-30-2014/equalizing-area-of-spectral-graphs-for-comparison
On Mon, Aug 11, 2014 at 11:50 AM, Benjamin Sugar
<goo...@skilfullycurled.org <mailto:goo...@skilfullycurled.org>> wrote:
would it be possible to just have images of different spectra and
have people compare the images they getting using the spectral
workbench. I wan't to keep it as simple as possible for people. I
won't have time to educate on any math at the workshop.
also, is the peak height the identifier then?
--
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Am I understanding this correctly (doubtful by here goes):
Peak height is associated with fluorescence spectroscopy not absorbance spectroscopy. YES
The peak that you see is from the laser. Everything after the peak is produced by the excited materials in the sample. (source: Oil Testing Kit page) YES
Samples are compared by area under the curve. The peak height of the laser can throw off the area under the curve as it is independant of the fluorescence from the sample. Let's say "shape" rather than area. This is for visula examination. You may have very differet shape but same area. To be able to use appropriate metric for comparison (mathematically), little more analysis required.
In order to a compensate, you can normalize the data using peak height normalization or using the red channel as an attenuator.
Follow up question to Jeff's note: http://publiclab.org/notes/warren/07-30-2014/equalizing-area-of-spectral-graphs-for-comparison
When you say the y-axis doesn't matter anymore, you're referring to the y-axis of the peak, right? Presumably it matters for the area under the curve?