declaring FilePart field

[Salil Wadnerkar]

Hi,

I am building a form that takes a multipart file input.

package controllers

import play.api.data.Form

import play.api.data.Forms._

import play.api.mvc.MultipartFormData.FilePart

import play.api.libs.Files.TemporaryFile

  val bookForm = Form(

    tuple(

      "name" -> nonEmptyText,

      "file" -> mapping[FilePart[TemporaryFile]] // <=== Here is the compilation error

    )   

  )

How should I declare my file input form field?

Thanks

Salil

[Guillaume Bort]

You can't do that. You have to handle the form itself and the attached
files separately. Check the documentation:

http://www.playframework.org/documentation/2.0.2/ScalaFileUpload

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[Salil Wadnerkar]

Thanks, but I also need this field to be part of a form that has other
form inputs inputs like text. So, without declaring this form, how can
I extract elements from it?
My understanding is I need to declare the form object first and then
call bindFromRequest on that.

[Salil Wadnerkar]

Modifying the subject according to the guideline.
Let me know how I can declare a form that has file part as a field.