Haskell beginner question

[Abhinav Gogna]

Going through learn you a haskell.

In recursion chapter, there is an implementation of take function. I am trying to implement it another way but keep getting compiler error "Not in scope: ‘as’"

Here is the code

take' :: Int -> [a] -> [a]
take' _ [] = []
take' x _
  | x _ <= 0 = []
  | otherwise x (a:as) = a : take' (x-1) as

Can someone tell me what is wrong with this program?

[Derek McLoughlin]

Guards are just boolean conditions, and you can't (without using an extension called PatternGuards) do pattern matching in them:

take' :: Int -> [a] -> [a]

take' _ [] = []

take' x (a:as)

  | x <= 0 = []

  | otherwise = a : take' (x-1) as

[Abhinav Gogna]

Thank you Derek!

[mustafa mert güntürkün]

Hi all i have a question;

im going to be final exam today 2 hour later.I should know ;

Haskell's address binding mechanism for these

-static 

-stack-dynamic

-explicit heap-dynamic and implicit heap-dynamic if u know the answer could u send me pls.. 

Thank you.