Question on path()

[andrei...@gmail.com]

Hi,

My graph looks something like this (length can be longer). What I need is all the different and distinct branches, eg {A,B,E,J}, {A,C,F,K}, {A,D,G,L}, {A,H,I.M}

My idea so far is an in-loop starting from A, get all the paths, but among them I receive as well the intermediary ones:

eg. The orange path is not needed. I need just the complete, final paths. 

==>[v[768], v[1792]] 

==>[v[768], v[1536]]

==>[v[768], v[1792], v[2048]]

That's my query: g.V.has('someProp','A').as('x').in.loop('x'){it.loops<100}{true}.path()

Any idea how I could do this with path()? And if it's not possible, any other ideas how I could do this? 

Thank you,

Andrei

[Daniel Kuppitz]

The {true} tells the loop step to emit all vertices, hence you'll see each and every path. This should work:

g.V.has('someProp','A').as('x').in().loop('x') {it.loops<100} {!it.object.inE().hasNext()}.path()

Now loop only emits those vertices that don't have an in-edge.

Cheers,

Daniel

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[andrei...@gmail.com]

Thanks a lot! It works :)