Creating a new instance of an entity using ndb has previously interacted with entity's data stored

[Robert Fischer]

Hi,

I'm creating a new instance of a model and it's getting the data from the previous model I created.

Any idea what could be happening here?

class Keyword(ndb.Model):

    user_owner = ndb.UserProperty()

    description = ndb.StringProperty(indexed=False)

    time_created = ndb.DateTimeProperty(auto_now_add=True, indexed=False)

    deleted = ndb.BooleanProperty(default=False)

    keyword_list = ndb.StringProperty(repeated=True, indexed=True) #Indexed

    required_keyword_list = ndb.StringProperty(repeated=True, indexed=False)

    threshold = ndb.IntegerProperty(indexed=False)

    last_found_on_id = ndb.StringProperty(indexed=False)

    ids_found_on = ndb.JsonProperty(default=[], indexed=False)

    times_found = ndb.ComputedProperty(lambda self: len(self.ids_found_on)) #Indexed

    time_last_found = ndb.DateTimeProperty(indexed=False)

class KeywordHandler(webapp2.RequestHandler)

    def post(self):

        ...

        logging.warning('Creating new keyword object.')

        keyword_to_save = Keyword()

        logging.warning('ids associated with keyword: %s %s %s' % (str(keyword_to_save.key), str(keyword_to_save), keyword_to_save.ids_found_on))

        ...

The first time I run this it works great:

WARNING  2012-07-28 18:27:32,403 frontend_keywords.py:176] ids associated with keyword: None Keyword() []

When run a second time I get this in my log file -- why is the ids_found_on already populated for a new model instance? The ids_found_on matches the previously created entity:

WARNING  2012-07-28 18:27:40,459 frontend_keywords.py:176] ids associated with keyword: None Keyword() ['ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNCAxMzo0NTozOC1zeW1hbnRlYyBuDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNCAxNjozNDo0Ni1kb2xpY2EgcHJvDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNCAxNzowMDowOS10cmVuZG5ldCA4DA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNCAxNzoyNzo1OS00MCBzY2VwdHJlDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNCAxNzozNDoyNi0ycGFjayBjcmFmDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAwNzowMDowMy1uZXRnZWFyIHB1DA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAwNzoxNjoxMC1waW9uZWVyIHZzDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAxNjo0ODo0Mi1jcm9jcyBjb3VwDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAxOTowMDo0OS1zYW1zdW5nIDgzDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAxOTozMzowOC1tZW5zIHdlYXJoDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNSAxOTo1Mjo1NC10cmFtb250aW5hDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNiAwMTo0MDozOS1jcmFmdHNtYW4gDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNiAxMjoxMjozOC1ib3cgcmFrZSB3DA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNiAxNzo1NDoyOC00MSB2b3JuYWRvDA', 'ahBkZXZ-ZGVhbHNjb3JjaGVyciwLEghSU1NFbnRyeSIeMjAxMi0wNy0yNiAxODowNDoyOC1sb2dpdGVjaCBoDA']

Thanks,

Robert

[Kaan Soral]

def GG():
  a=1

def testit(gg=GG()):
  a+=1
  print a

testit(); testit(); testit()

I didn't check your code much but may this be the problem?

[Kaan Soral]

Correction

On Saturday, July 28, 2012 11:35:39 PM UTC+3, Kaan Soral wrote:

def GG():
  a=1

def testit(gg=GG()):

  gg.a+=1
  print gg.a

[Guido van Rossum]

The "default=[]" is causing this. All instances share the same list object this way. You'll have to find some other way of initializing the value. Maybe you cna just use a repeated string property?

[Robert Fischer]

Thanks Guido,

I removed the default argument and things are working as expected.

-Robert

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