retrieve source code from code object as returned by compile()

[Justin Ezequiel]

Is there a way to get the original source?
I am trying to retrieve the main script from a py2exe'd old program.
The programmer neglected to commit to SVN before leaving.

Using "Easy Python Decompiler" I am able to get the source for the imported modules.
Using "Resources Viewer" from PlexData and some code I am able to retrieve the code object. I am however stumped as to how to retrieve the source from this code object.

PythonWin 2.5.4 (r254:67916, Dec 23 2008, 15:10:54) [MSC v.1310 32 bit (Intel)] on win32.
Portions Copyright 1994-2008 Mark Hammond - see 'Help/About PythonWin' for further copyright information.
>>> s = 'import time\nprint time.time()\n'
>>> c = compile(s, 'foo.py', 'exec')
>>> exec(c)
1398299623.77
>>> c
<code object <module> at 01E5C5C0, file "foo.py", line 1>
>>> for n in dir(c):
... if n.startswith('_'): continue
... print n
... a = getattr(c, n)
... print type(a)
... print `a`
... print
...
co_argcount
<type 'int'>
0

co_cellvars
<type 'tuple'>
()

co_code
<type 'str'>
'd\x00\x00d\x01\x00k\x00\x00Z\x00\x00e\x00\x00i\x00\x00\x83\x00\x00GHd\x01\x00S'

co_consts
<type 'tuple'>
(-1, None)

co_filename
<type 'str'>
'foo.py'

co_firstlineno
<type 'int'>
1

co_flags
<type 'int'>
64

co_freevars
<type 'tuple'>
()

co_lnotab
<type 'str'>
'\x0c\x01'

co_name
<type 'str'>
'<module>'

co_names
<type 'tuple'>
('time',)

co_nlocals
<type 'int'>
0

co_stacksize
<type 'int'>
2

co_varnames
<type 'tuple'>
()
>>> len(s)
30
>>> len(c.co_code)
27
>>>

[Gregory Ewing]

Justin Ezequiel wrote:
> Using "Easy Python Decompiler" I am able to get the source for the imported
> modules. Using "Resources Viewer" from PlexData and some code I am able to
> retrieve the code object. I am however stumped as to how to retrieve the
> source from this code object.

Easy Python Decompiler should be able to do that, but you
may need to delve into its innards a bit to find an entry
point where you can feed in a code object.

Alternatively you could create a .pyc file out of the code
object and then use Easy Python Decompiler on that. The
following snippet of code should do that:

import marshal
import py_compile
import time

with open('output.pyc', 'wb') as fc:
fc.write('\0\0\0\0')
py_compile.wr_long(fc, long(time.time()))
marshal.dump(codeobject, fc)
fc.flush()
fc.seek(0, 0)
fc.write(py_compile.MAGIC)

(Taken from:
http://stackoverflow.com/questions/8627835/generate-pyc-from-python-ast)

--
Greg

[Justin Ezequiel]

On Thursday, April 24, 2014 1:53:38 PM UTC+8, Gregory Ewing wrote:
> Alternatively you could create a .pyc file out of the code
> object and then use Easy Python Decompiler on that. The
> following snippet of code should do that:
>

> (Taken from:
>
> http://stackoverflow.com/questions/8627835/generate-pyc-from-python-ast)

Woohoo! Success! Thank you Greg!

[Amirouche Boubekki]

in python3, I do inspect.getsource(object) [doc], I don't know the limitations.

On Python 2, there is meta.

My interest is different, I use to retrieve the definition of function to submit it to a database, instead of stored procedures, but I have the source of the code. It can also be used to retrieve the ast.

--
https://mail.python.org/mailman/listinfo/python-list

[Gregory Ewing]

Amirouche Boubekki wrote:
> in python3, I do inspect.getsource(object) [doc

> <https://docs.python.org/3/library/inspect.html#inspect.getsource>], I

> don't know the limitations.

The limitation relevant here is that it requires the
original source file to be present. :-)

--
Greg