Execute SWRL rules using command line

[harshal patni]

Hello Everyone,

           I am new to Stardog. I have written a SWRL query (that does not make sense.. just for test). When I run the query using command line it gives an error - 

Command Line query - ./stardog query "testJena;reasoning=SL" "ClassTest1(?x), DPTest1(?x, "Test") -> ClassTest2(?x)"

Error - Not a valid query string or a file: ClassTest1(?x), DPTest1(?x, Test) -> ClassTest2(?x)

DB Name - testJena

Reasoning Type - SL (I think this includse SWRL queries as well)

Query explanation - All I am trying to say is that "if an instance of ClassTest1 has PropertyName 'Test'  then it should also be an instance of ClassTest2"

Could somebody help me resolve this issue? Am I making a mistake in the SWRL format

Thanks in advance,

Harsh

[Mike Grove]

On Tue, Nov 4, 2014 at 1:08 AM, harshal patni <patni....@gmail.com> wrote:

Hello Everyone,

           I am new to Stardog. I have written a SWRL query (that does not make sense.. just for test). When I run the query using command line it gives an error - 

Command Line query - ./stardog query "testJena;reasoning=SL" "ClassTest1(?x), DPTest1(?x, "Test") -> ClassTest2(?x)"

Error - Not a valid query string or a file: ClassTest1(?x), DPTest1(?x, Test) -> ClassTest2(?x)

Stardog only accepts SPARQL queries.

You might consider reading the chapter in the documentation [1] that explains how to use rules in Stardog.

Cheers,

Mike

[1] http://docs.stardog.com/owl2/#sd-User-defined-Rule-Reasoning 

DB Name - testJena

Reasoning Type - SL (I think this includse SWRL queries as well)

Query explanation - All I am trying to say is that "if an instance of ClassTest1 has PropertyName 'Test'  then it should also be an instance of ClassTest2"

Could somebody help me resolve this issue? Am I making a mistake in the SWRL format

Thanks in advance,

Harsh

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