Activity Question - Not Graded

[shubh...@gmail.com]

Isn't the answer for second part of this question 6 because under root 49, 7, 22, -35, 1729, -20000 are all integers. But it says Accepted Answer is 5.

[Jinal Raval]

Here (49)^(1/2) = 7 and 7 is also provided in the list. Need not count twice.

[Alistair Brae]

But what about taking square root of 49 as -7?

[shubh...@gmail.com]

By convention we take only positive square roots.

[Karun Agarwal]

But, it is not given anywhere that we have to count only the unique ones. Don't you think it should be explicitly mentioned that we have to find the unique integers?

[Christopher Raphael]

The unmodified list will have "6 counts" of "integer", since the question asks one to count the number of integers in the list. (did not ask for unique integers)

[Christopher Raphael]

let listOfReals = [ √3, 2.5, e, √49, 7, 22, pi, -35, √6, 1729, -20000 ];
let numberOfElementsInList = listOfReals.length; //=>length of the array = 11
let integerCount=0;

for(i=0; i<numberOfElementsInList; i++)
 {
  if(listOfReals[i]==INTEGER)
   {
   integerCount++;
   }
 }

Result> integerCount: 6
Because √49=7 and therefore will be counted as an integer.

On Monday, 5 October 2020 11:39:33 UTC+5:30, shubh...@gmail.com wrote:

[Venkatesan Shesha Srikanth]

Hi,

    You are right, there are 6 integers in the given list. But now, we have corrected the list. Thank you

Warm regards

srikanth venkatesan

IITM Online degree project

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