Didpeptide bond formation

[Thakkar Taniya]

Respected sir/mam,

Here in the screenshot in the first peptide highlighted in orange colour, the oxygen is negative as it has one extra electron with it and the next peptide (highlighted in dark purple) has positive charge on nitrogen because it accepted the hydrogen atom that only had it's proton but no eletcron and therefore nitrogen had to share his own electron to hydrogen . Now these two peptide wants to join by losing water so the carboxylic (orange one) will losse oxygen with its extra electron and nitrogen will losse first hydrogen that purple one which only had proton and the another hydrogen which has both proton and electron and now this forms water molecule

Summary of what I wrote:

1 Orange oxygen has one extra electron

2 Purple hydrogen has no electron

3 One more full hydrogen (having both proton and electron)

These three statements written above forms the water molecule. Please tell am I right?? Have I understood the dymics properly or is there any mistake. 

Please reply and help me out.

Sincerely, 

Taniya

[NOC23 CY30]

Yes, in a simplified language, it is correct.