a doubt

[Nirmala.M MCA]

a=[0,1,2,3]

for a[-1] in a:

    print(a[-1])

    

can u explain this code

[ARUN KUMAR]

i have also same double....

[16-ICS-041 Prateek]

see, you are taking a[-1] instead of i,  

so in first step you are setting a[-1]=0 (as loop will iterate in "a" list so now list will become  [0,1,2,0] ) then it will print a[-1] which is "0" now.

then in next step a[-1] will be 1 ,so 0 will be replaced by 1(new list [0,1,2,1]) it will print "1"

after that  a[-1] will be 2 so 1 will be replaced by 2 (new list [0,1,2,2]) and a[-1] will be "2"

and in last step a[-1] will be 2 since last updated list was [0,1,2,2]  so new list will also remain [0,1,2,2] and a[-1] will again print "2"

output will be -> 0

                             1

                             2

                             2

hope , this will help

On Friday, December 18, 2020 at 10:44:53 PM UTC+5:30 Nirmala.M MCA wrote: