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to Discussion forum for Foundations of Wavelets & Multirate DSP
Claim :F = \int_0^1 |f(t)|^2 dt is a norm
In the definition of a norm, the above form F does not satisfy the scaling property.
|\alpha F| \neq |\alpha| |F|. On the other hand F^{1/2} is a valid norm.
Kindly clarify
nikunj
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Apr 8, 2016, 1:22:28 AM4/8/16
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to Discussion forum for Foundations of Wavelets & Multirate DSP, vijay....@gmail.com
yeah you are correct, F is not valid definition of norm since it does not satisfy scaling property. F^{1/2} is a valid norm which is nothing but euclidean norm or L_2 norm for signal defined in interval [0,1].