We know that 3 bit binary no.'s are: 000, 001,,010,011,100,,101,110 and 111. So in the form of 2^3=8.
So 1 bit binary no. must be, 0 and 1.
As we know range of unsigned binary number is from 0 to 2^n - 1.
So 0 bit binary would be from 0 to 2^0 - 1=0 only and hence 0 only?