EQUATION OF A TANGENT AT ANY GIVEN POINT IN A PARABOLA

Aswin M S

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Nov 18, 2020, 4:24:13 PM11/18/20

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Dear Sir/Madam,

Couldn't find the equation of tangent at any given point in a parabola in the Week 4 slides. And the equation was not a part of the lecture and there was no explanation either. Will there be questions from this area? If so please give an explanation of the equation. Thanks for the kind attention.

Thank You.

Yours faithfully

Aswin M S

MANOJ KUMAR Narayan

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Nov 18, 2020, 10:01:27 PM11/18/20

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By google:

The equation of the tangent to the parabola y2=4ax at a point (x1,y1) is given by yy1=2a(x+x1).

Malabika Guha Mustafi

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Nov 18, 2020, 10:17:09 PM11/18/20

to Discussion forum for Mathematics for Data Science I, MANOJ KUMAR Narayan, aswin...@gmail.com

2ax + b

It is there .

slope=2ax +b

@ Manoj

Is it Y2 or Y^2?

For this exam, slope=2ax+b

satyasanthi ponnala

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Nov 19, 2020, 1:49:17 AM11/19/20

to Discussion forum for Mathematics for Data Science I, Malabika Guha Mustafi, MANOJ KUMAR Narayan, aswin...@gmail.com

you use slope ,point form

find slope of parabola

y-y1=m(x-x1)

put the values of x1,y1 in the eqation

m=dy/dx=slope 2ax+b

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