Week 3 - Graded Assignment - Q5 - Solution Doubt

[Zohair Merchant]

The given solution mentions:

Case 1:

|c + 5| = |c − 8| =⇒ 5 = −8 which is not possible.

Case 2:

|c + 5| = |−(c − 8)| =⇒ c = 3/2

.

Even if c-8 is not possible, how can we convert c-8 to -(c-8) which is c+8.

How can we change the result (c-8) of the distance formula between 2 parallel lines to -(c-8)?

[Malabika Guha Mustafi]

Case 2:

 one of C+5 or C-8 is negative (within modulus sign)

If both the result are  positive within modulus sign  then 5=8 which is not possible. (considering first case)

so, we will get 

C+5= -(C-8)

or , 2C = 3

or, C=3/2

 [ we can not consider absolute value for comparison  since it always generates positive value].

[Mathematics 1 Support 2]

Hi Zobair,

There is nothing called c-8 is not possible.

Here the only thing which is not possible is  5 = -8.

Best wishes,

Rahul

[Zohair Merchant]

I understand c-8 will lead to 5=-8 which is not possible.

But I'm saying the result of the distance formula was |c-8|

then in case 2, How can we take -(c-8). because that leads to c+8, which is different from c-8, right?

Could someone please explain? 

I think I'm going wrong somewhere in converting from the mod.

[Zohair Merchant]

So considering one of the values is minus we multiply whole of c-8 by -1, right?

If so then can we multiply C+5 by -1?

On Thursday, November 5, 2020 at 7:16:27 PM UTC+5:30 Malabika Guha Mustafi wrote:

[Malabika Guha Mustafi]

yes, any side.