qualifer paper question

Priyanshu Singh

unread,

Nov 21, 2020, 5:02:24 AM11/21/20

to Discussion forum for Mathematics for Data Science I

its a emergency reqeust please can anyone explain these 2answer ni a brie f way

how to find out please

pio.jpg

raghavendra kumar

unread,

Nov 21, 2020, 6:18:24 AM11/21/20

to Priyanshu Singh, Discussion forum for Mathematics for Data Science I

Hi,

There are two ways one with Venn diagram and other with checking cardinality of sets

I have attached for cardinality

Hope this helps

On Sat, 21 Nov, 2020, 3:32 pm Priyanshu Singh, <priyanshu...@gmail.com> wrote:

its a emergency reqeust please can anyone explain these 2answer ni a brie f way
how to find out please

--
You received this message because you are subscribed to the Google Groups "Discussion forum for Mathematics for Data Science I" group.
To unsubscribe from this group and stop receiving emails from it, send an email to ma1001-discus...@nptel.iitm.ac.in.
To view this discussion on the web visit https://groups.google.com/a/nptel.iitm.ac.in/d/msgid/ma1001-discuss/cfb19143-e910-4776-9203-74b328445325n%40nptel.iitm.ac.in.

IMG_20201121_164529.jpg

Raaja Rajeshvari M

unread,

Nov 21, 2020, 7:07:46 AM11/21/20

to Discussion forum for Mathematics for Data Science I, raghavendr...@gmail.com

Could you please explain this?

Screenshot (105).png

Jai Hanani

unread,

Nov 21, 2020, 7:30:00 AM11/21/20

to Discussion forum for Mathematics for Data Science I, priyanshu...@gmail.com

A U B U C = A + B + C - (A ∩ B + B ∩ C + C ∩ A) + (A ∩ B ∩ C)

Deepak Sirohiwal

unread,

Nov 21, 2020, 8:02:06 AM11/21/20

to Discussion forum for Mathematics for Data Science I, Raaja Rajeshvari M

Here Domain and Codomain both are Integer. So, this function can only be bijective if it an Injective and surjective (codomain = Range).

So, According to the first option, the function will be

f(x)=B; let's take the value of B =1

so for every Integer, the value will be the same. so it can not be injective.

2nd option: If you take the value of A =1 or -1 and any value of B(here B has a condition that it is an integer), you will get a distinct value of Y for every X and the range will be equal to the codomain which is Integer.

3rd Option: Same as 1st option

4th option: If B=0 then f(x)=Ax. Let A=1. So, for every value of X, we will get a distinct Y value. So this can be an Injective. But what if we take the value of A=2.

If the value of A=2 then f(x)=2x this will give only even values and will not cover the odd values. (Range= even integers)

So, to meet the condition of surjection the Range should be equal to the codomain, which is not the case here.

So the correct option will be 2nd.

Reply all

Reply to author

Forward