the slope of the given line 3x+4y−8=0 is -3/4
Hence, the slope of the perpendicular is 4/3.
y = (4/3)x + c is the equation of line we need.
In order to find c, substitute the point (3, 4) into the above equation.
4 = (4/3) * 3 + c ==> c = 0
Thus, equation of the line we require is y = (4/3) * x ==> 4x - 3y = 0. Multiplying 2 on both sides of the equation, we get 8x - 6y = 0