We get , y= - square(b)/4a + c ( for maximum value or minimum value after putting x=-b/2a) as follows:-
y= a(xsquare ) + bx+c
= a. square(-b/2a) + b. (-b/2a) +c
=square(b)/4a - square(b)/ 2a + c
= - square(b)/4a + c [ if you can remember , it is direct formula to get maximum/minimum]