Graded Assignment 3 - Question 10 | Opinions Required.

[Aman Kumar]

Options which I got correct :

Value of SSE Calculated by Student A = 14

• The SSE would be the summation of ( P - RT/v ) ^ 2
• Applying this concept the SSE for A is 14 and for B is 18

But can anyone explain me this ? 

Why can't A and B have the same fit ?   

• Because as per question - (Both students use the same gaseous sample having v=16.6m3/mol and reported the approximate value of RR as 8.3J/(KΔmol) using the minimization of sum squared error)  
• Since the constants in the equation calculated by both of the students are same, the fit has to be same right?

Do correct me if I'm wrong. Any help would be appreciative. 

[nee...@gmail.com]

Because data collected by them is different. Thats why with the same equation there see is different.

[Aman Kumar]

I thought the value of the constant obtained is the result of the data collected, and whosoever obtained less SSE has a good fit. But since the constants were provided in the question itself, I thought they both have the same fit. 

It'll be more clear if anyone from the forums or Course Support can explain this to me. 

Thanks for the help btw,

[Malabika Guha Mustafi]

Better fit means how the data are close enough to a line (with m slope here it is 0.5).

Y=mx + c

in this problem, m=0.5 and c=0

but y value( observation ) are different for A and B.

Though m is constant but due to the different y (observed) values, A 's recorded values are nearer to that line compare to B's value. it is reflected in SSE.

so. A 's records are better fit than B.

hope, it hepls you.

[subhajit POD]

Please check the portal for a detailed notes on SSE. It is in the resources from the instructor of week 3. 

Hope it will help. 

Best

Subhajit