Week 4 - Tutorial 6 - Doubt

[Zohair Merchant]

In Week 4, Tutorial 4,  part B of the question the function of curve given is f2(x) = (x-4)^2.

I understood that the root is 4 as x=4 when put in the equation will give us the y = 0 meaning the  x-intercept (4,0).

Doubt:

But how is (4,0) the vertex? How can we calculate that?

As the only way I know to find the vertex is to get the x-coordinate of the vertex from the axis of symmetry's equation x=-b/2a and then substitute x-coordinate in the function to get the y-coordinate of the vertex.

Regards,

Zohair

[DHARMA TEJA GODUMALA]

At max or minimum point on the curve the slope will be Zero . At X=4 slope is Zero so it is minimum point as per question which is also called as vertex. Even the axis of symmetry is derived from the slope of quadratic equation. But it is considered indirectly that't it.