is there a name/function for this task, similar to expand

[Daniel Davidson]

I see expand does: 

    print([[1, 2, 3], ['a', 'b']].expand((i) => i))

which gives:

    (1, 2, 3, a, b)

I want to throw in a function on the list:

    print(???[1, 2, [3, 4, [5, 6]], 7].???)

to give Iterable:

    (1, 2, 3, 4, 5, 6, 7)

Thanks,

Dan

[Lasse R.H. Nielsen]

Seems like you want a "deep flatten".

A naive implementation could be:

flatten(iterable) => iterable.expand((v) => v is Iterable ? flatten(v) : [v]);

/L

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[Daniel Davidson]

Great, thanks! I'll use that for now.

Is this something that is generally useful and maybe worthy of quiver.iterables?

Thanks,

Dan