Is it possible that class object can have a member of class itself?

[진호용]

I am trying to make a class with a dictionary member that its value is class itself.

ex)

```

class A:

  def __init__(self):

    self.dictionary = { }  # key is integer, value is class A itself

```

Is it possible?

Code below is my try.

```

import numpy as np

import numba

from numba import jit, jitclass, types, typed

dict_type = numba.deferred_type()

node_spec = [

    ('key', numba.uint32),

    ('data', numba.uint32[:]),

    ('count', numba.uint32),

    ('children', dict_type)

]

@numba.experimental.jitclass(node_spec)

class Node:

    def __init__(self, key, data=None):

        self.key = key

        self.data = data

        self.count = 0

        self.children = {}

node_instance = Node.class_type.instance_type

dict_type.define(numba.typeof(typed.Dict.empty(

    key_type=numba.uint32,

    value_type=node_instance

)))

```

[Siu Kwan Lam]

The error is from 

```

typed.Dict.empty(

    key_type=numba.uint32,

    value_type=node_instance

))

```

because it is creating a Dict instance but `node_instance` is still not fully defined.

Spell the type with `types.DictType(numba.uint32, node_instance)` instead.

So the last line looks like:

```

dict_type.define(types.DictType(numba.uint32, node_instance))

```

Btw, I recommend using the Numba Discourse forum (https://numba.discourse.group/) for future questions and discussions.

-Siu

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