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Stardog literal comparison behaviour
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zhilia...@gmail.com
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Aug 18, 2015, 2:02:28 AM
8/18/15
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to Stardog, naru...@gmail.com
Hi Stardog team,
Given the below data, which I imported using the Sesame api,
<owl:DatatypeProperty rdf:about="
http://w.co/mfd#hasRevenue
">
<rdfs:domain rdf:resource="
http://w.co/mfd#Manufacturer
"/>
<rdfs:range rdf:resource="&xsd;long"/>
</owl:DatatypeProperty>
<owl:NamedIndividual rdf:about="
http://w.co/mfd#Apple
">
<rdf:type rdf:resource="
http://w.co/mfd#Manufacturer
"/>
<hasRevenue rdf:datatype="&xsd;long">182795000000</hasRevenue>
<hasName xml:lang="en">Apple Inc</hasName>
<manufacture rdf:resource="
http://w.co/mfd#iPhone5
"/>
<manufacture rdf:resource="
http://w.co/mfd#iPhone6
"/>
<rdfs:label xml:lang="en">Apple Inc</rdfs:label>
</owl:NamedIndividual>
I expected the following query to yield results, yet it didn't. Changing the datatype from <
http://www.w3.org/2001/XMLSchema#long
> to <
http://www.w3.org/2001/XMLSchema#float
> or <
http://www.w3.org/2001/XMLSchema#double
>
yielded the expected results. Please confirm if this is a bug.
SELECT distinct ?s WHERE { ?s <
http://w.co/mfd#hasRevenue
> ?o1 . FILTER( ?o1 > "10"^^<
http://www.w3.org/2001/XMLSchema#long
> )} -> 0 results
SELECT distinct ?s WHERE { ?s <
http://w.co/mfd#hasRevenue
> ?o1 . FILTER( ?o1 > "10"^^<
http://www.w3.org/2001/XMLSchema#integer
> )} -> 0 results
Further checking with the following query
SELECT (datatype(?o1) AS ?datatype) WHERE { ?s <
http://w.co/mfd#hasRevenue
> ?o1 }
yields <
http://www.w3.org/2001/XMLSchema#integer
>.
We are using Stardog v3.0.
Evren Sirin
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Aug 18, 2015, 2:25:12 AM
8/18/15
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to Stardog, naru...@gmail.com
On Tue, Aug 18, 2015 at 2:02 AM, <
zhilia...@gmail.com
> wrote:
> Hi Stardog team,
>
> Given the below data, which I imported using the Sesame api,
>
>
> <owl:DatatypeProperty rdf:about="
http://w.co/mfd#hasRevenue
">
> <rdfs:domain rdf:resource="
http://w.co/mfd#Manufacturer
"/>
> <rdfs:range rdf:resource="&xsd;long"/>
> </owl:DatatypeProperty>
>
> <owl:NamedIndividual rdf:about="
http://w.co/mfd#Apple
">
> <rdf:type rdf:resource="
http://w.co/mfd#Manufacturer
"/>
> <hasRevenue rdf:datatype="&xsd;long">182795000000</hasRevenue>
> <hasName xml:lang="en">Apple Inc</hasName>
> <manufacture rdf:resource="
http://w.co/mfd#iPhone5
"/>
> <manufacture rdf:resource="
http://w.co/mfd#iPhone6
"/>
> <rdfs:label xml:lang="en">Apple Inc</rdfs:label>
> </owl:NamedIndividual>
>
>
>
> I expected the following query to yield results, yet it didn't. Changing the
> datatype from <
http://www.w3.org/2001/XMLSchema#long
> to
> <
http://www.w3.org/2001/XMLSchema#float
> or
> <
http://www.w3.org/2001/XMLSchema#double
>
> yielded the expected results. Please confirm if this is a bug.
>
> SELECT distinct ?s WHERE { ?s <
http://w.co/mfd#hasRevenue
> ?o1 . FILTER(
> ?o1 > "10"^^<
http://www.w3.org/2001/XMLSchema#long
> )} -> 0 results
> SELECT distinct ?s WHERE { ?s <
http://w.co/mfd#hasRevenue
> ?o1 . FILTER(
> ?o1 > "10"^^<
http://www.w3.org/2001/XMLSchema#integer
> )} -> 0 results
Yes, this is a bug and we have an open ticket for this issue (#643).
>
> Further checking with the following query
>
> SELECT (datatype(?o1) AS ?datatype) WHERE { ?s <
http://w.co/mfd#hasRevenue
>
> ?o1 }
>
> yields <
http://www.w3.org/2001/XMLSchema#integer
>.
This is related to literal canonicalization and it is the expected
result (xsd:integer is infinite and it is a supertype of xsd:long).
See [1] for literal canonicalization.
Best,
Evren
[1]
http://docs.stardog.com/#_canonicalized_literals
>
> We are using Stardog v3.0.
>
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