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Code-Review | +1 |
return !!tasks_model_.selected_task();
do we need this?
// If there is a selected task, we will save its `task_list_id` and
// `task_id`; otherwise, we will store an empty dict.
```suggestion
// If there is a selected task, we will save its `task_id.list_id` and
// `task_id.id`; otherwise, we will store an empty dict.
```
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Commit-Queue | +1 |
tbarzic@ would you mind reviewing the change to the tasks API?
return !!tasks_model_.selected_task();
Sean Kaudo we need this?
It's somewhat conventional for pointers so you don't accidentally invoke the `()` operator. Strictly speaking, it's not necessary here.
// If there is a selected task, we will save its `task_list_id` and
// `task_id`; otherwise, we will store an empty dict.
```suggestion
// If there is a selected task, we will save its `task_id.list_id` and
// `task_id.id`; otherwise, we will store an empty dict.
```
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