This is a bug report for perl from perl-...@ton.iguana.be,
generated with the help of perlbug 1.34 running under perl v5.8.2.
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[Please enter your report here]
perl -wle '@F="A".."BZ"; $_="a"; s/./<$F[@a="b"..$&]>/; print; print"a=@a"'
Argument "b" isn't numeric in range (or flop) at -e line 1.
Use of uninitialized value in range (or flop) at -e line 1.
Use of uninitialized value in range (or flop) at -e line 1.
<B>
a=0
I expected $& to be "a", so @a should become (a b c ....z), so fetch
element 26 from @F, which should be "Z"
The 'Argument "b" isn't numeric in range (or flop) at -e line 1.' seems to
indicate $& is undef which in my perl still causes @a to become (0)
(this was bug 24735, but even with that fixed I just expect that now
@a will be () and it will output <A>, which is still wrong).
However, mentioning $& in the real string body will make things work
as expected:
perl -wle '@F="A".."BZ"; $_="a"; s/./$&<$F[@a="b"..$&]>/; print; print"a=@a"'
a<Z>
a=b c d e f g h i j k l m n o p q r s t u v w x y z
[Please do not change anything below this line]
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Flags:
category=core
severity=low
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Site configuration information for perl v5.8.2:
Configured by ton at Sun Jan 4 19:19:06 CET 2004.
Summary of my perl5 (revision 5.0 version 8 subversion 2) configuration:
Platform:
osname=linux, osvers=2.6.0, archname=i686-linux-64int-ld
uname='linux quasar 2.6.0 #3 thu dec 18 18:22:48 cet 2003 i686 gnulinux '
config_args=''
hint=recommended, useposix=true, d_sigaction=define
usethreads=undef use5005threads=undef useithreads=undef usemultiplicity=undef
useperlio=define d_sfio=undef uselargefiles=define usesocks=undef
use64bitint=define use64bitall=undef uselongdouble=define
usemymalloc=y, bincompat5005=undef
Compiler:
cc='cc', ccflags ='-fno-strict-aliasing -I/usr/local/include -D_LARGEFILE_SOURCE -D_FILE_OFFSET_BITS=64',
optimize='-O2 -fomit-frame-pointer',
cppflags='-fno-strict-aliasing -I/usr/local/include'
ccversion='', gccversion='3.4.0 20031231 (experimental)', gccosandvers=''
intsize=4, longsize=4, ptrsize=4, doublesize=8, byteorder=12345678
d_longlong=define, longlongsize=8, d_longdbl=define, longdblsize=12
ivtype='long long', ivsize=8, nvtype='long double', nvsize=12, Off_t='off_t', lseeksize=8
alignbytes=4, prototype=define
Linker and Libraries:
ld='cc', ldflags =' -L/usr/local/lib'
libpth=/usr/local/lib /lib /usr/lib
libs=-lnsl -ldb -ldl -lm -lcrypt -lutil -lc
perllibs=-lnsl -ldl -lm -lcrypt -lutil -lc
libc=/lib/libc-2.3.2.so, so=so, useshrplib=false, libperl=libperl.a
gnulibc_version='2.3.2'
Dynamic Linking:
dlsrc=dl_dlopen.xs, dlext=so, d_dlsymun=undef, ccdlflags='-rdynamic'
cccdlflags='-fpic', lddlflags='-shared -L/usr/local/lib'
Locally applied patches:
---
@INC for perl v5.8.2:
/usr/lib/perl5/5.8.2/i686-linux-64int-ld
/usr/lib/perl5/5.8.2
/usr/lib/perl5/site_perl/5.8.2/i686-linux-64int-ld
/usr/lib/perl5/site_perl/5.8.2
/usr/lib/perl5/site_perl
.
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Environment for perl v5.8.2:
HOME=/home/ton
LANG (unset)
LANGUAGE (unset)
LD_LIBRARY_PATH (unset)
LOGDIR (unset)
PATH=/home/ton/bin.Linux:/home/ton/bin:/home/ton/bin.SampleSetup:/usr/local/bin:/usr/local/sbin:/usr/local/jre/bin:/home/oracle/product/9.0.1/bin:/usr/local/ar/bin:/usr/games/bin:/usr/X11R6/bin:/usr/share/bin:/usr/bin:/usr/sbin:/bin:/sbin:.
PERL_BADLANG (unset)
SHELL=/bin/bash
If I add a /e modifier on the end of your s///, and fix up the
replacement section, I get the following:
perl -wle '@F="A".."BZ"; $_="a"; s/./join $F[@a="b"..$&], "<", ">"/e; print; print"a=@a"'
<Z>
a=b c d e f g h i j k l m n o p q r s t u v w x y z
: I expected $& to be "a", so @a should become (a b c ....z), so fetch
: element 26 from @F, which should be "Z"
I think that I got what you expected. When you want to evaluate code
in a regular expression you must add the /e modifier. I think that
this is notabug. Am I missing something?
Casey West
--
Good Idea: Taking a deep breath before jumping into a swimming pool.
Bad Idea: Taking a deep breath after jumping into a swimming pool.
Oh, that's interesting. I think it's a real bug.
The subscript of an array element is always evaluated as code, even in
a double-quoted string:
$ perl -le '@F=qw(a b c d e); print "$F[1+2]"'
d
I see no reason why C<1+2> should work but C<@a = "b" .. $&> should not.
--
Chip Salzenberg - a.k.a. - <ch...@pobox.com>
"I wanted to play hopscotch with the impenetrable mystery of existence,
but he stepped in a wormhole and had to go in early." // MST3K
Perl evaluates code inside array and hash indexes inside double-quotish
strings. MJD takes advantage of this with his Interpolation module
(e.g. print "3 + 4 = $E{3+4}";). The warnings from Ton's example indicate
that the flip flop operator is being executed; the bug is that $& isn't
being set.
Ronald