There is no question about it. NONE. Read on:
There IN FACT **IS** a orderly relationship between all the consonants
In "Sanford Wallace" and all those in "Taylor Jimenez" AND there
is an orderly relationship between all the vowels!!
On the left the Sanford Wallace consonants and on the right those of
"Taylor Jimenez":
Note: One consonant from first name and one from last is +1 one, then
otherwise
2 names letter switches show 2 different patterns: Details:
From first name 'Sanford' for "Taylor":
d - 5 = y
n - 2 = l
r - 0 = r
s + 1 = t
(incrementing pattern CHANGE -1, -2, -3, going from plusing 1 to plusing 0
(-1 increment change)
then to plusing -2 (-2 increment change from previous)
then to plusing -5 (-3 increment change from previous))
c (unmatched; 'Sanford' shorter than "Taylor" by one consonant)
From 'Wallace' (plus one consonant from Sanford) FOR "Jimenez":
l + 1 = m
l + 2 = n
w + 3 = z
f + 4 = j
(pattern: plus 1, plus 2, plus 3, plus 4 -- all increments are +1 more
THAN the last)
(those are all the consonants in "Taylor Jimenez")
Now vowels:
The vowels in the first names Taylor and Sanford are the same.
The vowels in Jimenez are one vowel away from the vowels in Wallace
That is The 2 "a"s in Wallace become "e"s and the "e" becomes an "i"
I could write the program that does this myself!!!!