a) The expected number of dead chapatsu freeters
b) The 95% confidence interval for total dead
2. Suppose a sound truck full of nationalists pulls up next to an
international school. Ten nationalists armed with high-powered slingshots
fire 5 ball bearings each, aiming at windows. Assuming that the average
punctured window scatters 5 pieces of glass shards at high speed, and each
projectile has a 1% chance of blinding children, calculate the expected
number of blinded children.
3. Suppose a meteorite strikes the middle of Roppongi Crossing, and the
probability of death with respect to distance (in meters) from impact is
expressed by the equation
1/25 * e ^ (-d/25). Assuming that there is an average of one black pimp or
Chinese prostitute per square meter, calculate the total number of
incinerated criminals in a 100-meter radius.
ANSWERS:
1a) Expected total doses = 500/10 = 50.
Expected doses consumed by chapatsu freeters = 50 * 0.4 = 20.
Chapatsu freeters killed by dosage = 20 * .7 = 14.
b) Assuming a normal distribution, the 95% interval for the average dose is
Mean(dose) +/- (SD(dose) / sqrt(n) * Z(.975)) =
10 +/- (5 / sqrt(50) * 1.96) = 10 +/- 1.39 = (8.61, 11.39)
minimum case: 500 / 8.61 = 58.07
minimum deaths: 58.07 * 0.7 = 40.65
maximum case: 500 / 11.39 = 43.90
maximum deaths: 43.90 * 0.7 = 30.73
Therefore the 95% confidence interval for the total death toll is (30.73,
40.65).
2. Blinded children = 0.01 * (number of ball bearings + number of glass
shards)
= 0.01 * (50 + 50*5)
= 0.01 * (300) = 3.
3. Integral(0,100) of pi* r^2 * 1/25 * e^(-d/25) = (integrating by parts) =
1/25 * -25*pi*10^4*(e^-4) + 50*pi*625*.9084 = 1/25(-14385 + 89179) =
1/25(74,794)
Approximately 2,992 criminals.
>1. Suppose a terrorist adds ricin to the steel milk jugs at the Shibuya
>Starbucks. The jug contains 500 ml of milk, and the average person uses 10
>ml of milk, with a standard deviation of 5 ml. Suppose further that the
>customers are 40% chapatsu freeters, 20% English teachers, 10% enjo kosai
>teens, and 30% salarymen with bad breath. Suppose the ricin has a 70% chance
>of killing the victim within 3 days. Calculate
>
>a) The expected number of dead chapatsu freeters
Man. the old kill filter's getting a workout today.
My lord, you have got some free time on your hands.
BTW, I think you missed a decimal point in there. You'd better go back over
your calculations.
Helpfully Yours,
Ryan
--
Regards,
Ryan Ginstrom
Whatever the answer is.. hopefully it takes out a couple engrish teachers in
the process.
zero, they don't use steel milk jugs at Starbucks, they use plastic jugs.
> 2. Suppose a sound truck full of nationalists pulls up next to an
> international school. Ten nationalists armed with high-powered slingshots
> fire 5 ball bearings each, aiming at windows. Assuming that the average
> punctured window scatters 5 pieces of glass shards at high speed, and each
> projectile has a 1% chance of blinding children, calculate the expected
> number of blinded children.
what gauge rubber band in the slingshots?
> 3. Suppose a meteorite strikes the middle of Roppongi Crossing, and the
> probability of death with respect to distance (in meters) from impact is
> expressed by the equation
>
> 1/25 * e ^ (-d/25). Assuming that there is an average of one black pimp or
> Chinese prostitute per square meter, calculate the total number of
> incinerated criminals in a 100-meter radius.
I know the meteorite you speak of, and it is destined to strike on New
Year's day at 10am. The ends up killing a bunch of grandmothers in Kimono
who are waiting at Almond for their families to meet them. It becomes a
national tragedy and the head of the Japan Space Agency offers his
resignation as a sign that he is truly sorry.
<tedious argle-bargle snipped>
This is all very well, but when are you going to give us your account
of your stay in Japan, like what you promised us?