> Oh, let's have fun - what is the TANGENTIAL velocity on the "surface"
> of a spinning electron (point source, ya know).
Taken as a classical electron, it is greater than the light velocity.
But it is a quantum object, described by the Dirac equation.
--
~~~~ %20cl...@free.fr%20 LPF
Liberty, Equality, Profitability.
As we know, dirac's spin is not rotation about anything in physical space.
best
penny
>Taken as a classical electron, it is greater than the light velocity.
>But it is a quantum object, described by the Dirac equation.
Lorentz wrote many papers on electrons as classically rotating objects of
finite size.
In fact, he first published E=mc^2 ( yes, before Einstein ) in this special
context.
> As we know, dirac's spin is not rotation about anything in physical
> space.
Dear Penny,
The rotation of the energy flux at the boundary, i.e. where
grad (psi^bar psi) /= 0.
>The rotation of the energy flux at the boundary, i.e. where
>grad (psi^bar psi) /= 0.
Not exactly.
> Spin is an operator that takes its values in a spin bundle. Nothing in
> physical space rotates. There is a factor of two difference from the
> physical space case, because of the double covering of the orthogonal
> group by the spin group.
Not exactly. The spin is the observable associated to the spin
operator, which is a rotation generator. For half integral spin, it is
the one of a Cartan representation. The spin is associated to the
transformation property of the wave function by a rotation, it is a
Noether invariant. It isn't a vector, but a rank 2 antisymmetric
tensor.
> >The rotation of the energy flux at the boundary, i.e. where
> >grad (psi^bar psi) /= 0.
> Not exactly.
The energy flux have a moment wrt the classical center of the electron,
that is, the expectation value of the position <psi| x |psi>.
If in a material the spins are flipped, it gets an angular momentum.
That's an experimental fact.
CF: Spin Geometry by Michelson and Lawson.
>Not exactly. The spin is the observable associated to the spin
>operator, which is a rotation generator. For half integral spin, it is
>the one of a Cartan representation.
>The spin is associated to the
>transformation property of the wave function by a rotation, it is a
>Noether invariant. It isn't a vector, but a rank 2 antisymmetric
>tensor.
Quaint.
Out of date by seventy years. It isn't a vector but a section of a clifford
operator bundle. Yes, the equation has an infinitesimal noether symmetry etc.
But where and on what does this equation operate?
Not on physical space. In your language,but on an internal symmetry space. That
is on a bundle.
>The energy flux have a moment wrt the classical center of the electron,
>that is, the expectation value of the position <psi| x |psi>.
>If in a material the spins are flipped, it gets an angular momentum.
>That's an experimental fact.
It is your interpetation of a different mathematical fact.Think "internal
symmetry space".
And even more interesting is the Metaplectic group bundle because that gives
geometric quantization.
best
penny