backward reference

[niva]

Hi,

I am using this kind of code in order to modify line content :

let patternOfxembh='^.*one="\(\d\+\)".*two="\(\d\+\)"'
if line =~ patternOfxembh
echo line
endif

The recognition is working well and then I can echo my line but is it possible to do an echo of backward reference: value of \(\d\+\).

I would like to avoid to use substitute and using again the same pattern on the line.

Thank you

[Ben Fritz]

You cannot use the captured groups at a later time after doing a =~ or substitute().

However, you can use the matchlist() function to give you a list of all the matches which you can use later. This function returns an empty list if there are no matches, so to avoid doing regex matching twice you could do:

let lineMatches = matchlist(...)
if !empty(lineMatches)
echo line
...
endif

[ni va]

It works perfectly :)

2012/10/30 Ben Fritz <fritzo...@gmail.com>

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