We can probably assume that the amount of heat energy absorbed by food
in a microwave is approximately proportional to the time spent in it.
We can assume further that the amount of energy to boil the peas
themselves is fixed. I have no idea what amount of peas you mean, nor
of their specific heat, though I can guess that, since living things
mostly consist of water, it won't be much different from that of
water. But anyway, to raise a given amount of peas to boiling
requires a given input into the system which is unaffected by how much
water you add. Let's call this amount of energy P.
However the water added will lose heat energy during the transfer, and
not all of that heat will go into the peas, it being necessary to
replace any amount lost by energy from the microwave. Further, the
more water you add, the more heat will go astray, and have to be
replaced.
Let us consider two quantities of water as examples.
Suppose that first we add just enough water to cover the peas. Some
of its heat will be transferred to the peas, but some will be lost to
the environment. Let's call the amount of energy introduced by this
amount of water W, and the amount lost dW. Thus the microwave has to
supply P - W + dW to bring the peas to the boil.
Let's now try doubling the amount of water. The amount of heat
required from the microwave is now P -2W + 2dW.
Well, actually, it's more, because heat is being lost to the
environment all the time, even while the microwave is cooking the
food, and because the greater amount of water will take longer to
heat, more heat will lost to the environment during the process, and
have to be replaced by even longer cooking.
So a lot depends on whether dW is greater than W. It is relevant here
is that the amount of heat lost is dependent largely on the heat
gradient - that is the hotter the water is relative to its
surroundings, the greater the heat gradient between itself and its
surroundings, so the more rapidly it is losing energy to those
surroundings. The water will be losing heat most rapidly at the
moment of power disconnection.
However, a full analysis would require actual numbers which you
haven't supplied and which, OOTTOMH, would be difficult to guess with
sufficient accuracy. Without hard numbers, it's not possible to say
either way.
Of course, if you're concerned about the energy consumption of the
entire process, including the kettle, not just narrowly about the time
spent in the microwave, it is certain you should use as little water
as possible. Certainly, that's what I would do.
On Mon, 20 May 2013 02:28:12 +0100, Bill Wright <
bi...@invalid.com>
wrote:
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