Denemedenn

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Jan 9, 2022, 1:16:51 AM1/9/22

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Jan 10, 2022, 1:26:51 AM1/10/22

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3x<=f(x)<=2x ve f(x)<0 olduğundan,

fofof(x)=fof(2x)=f(4x)<=8x

veya

fofof(x)=fof(3x)=f(9x)>=27x 'tir.

27x<=fofof(x)<=8x

f(x)<0 olduğundan

fofof(x)<=f(x)'tir.

f(x) fonksiyonu azalan olmayabilir.

-9<=f(-3)<=-6

-6<=f(-2)<=-4

f(-3), f(-2)'e eşit olabilir.

fof(-3)=f(-6)<=-12

fof(-3)=f(-9)>=-27

fof(-3)<=-9'dur.

Cevap I ve III.

On Sunday, January 9, 2022 at 9:16:51 AM UTC+3 mathd...@gmail.com wrote:

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