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Oct 10, 2021, 8:01:23 AM10/10/21

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Oct 12, 2021, 5:27:35 AM10/12/21

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Yerel maksimum değerleri f'(x)=0 olduğu noktalardır.

f(x)=2x^3-12x^2+6x+18

f'(x)=6x^2-24x+6=6(x^2-4x+1)=0

x=2±sqrt(3)

Yerel maksimum(x=2-sqrt(3))=12sqrt(3)-2

Yerel minimum(x=2+sqrt(3))=-12sqrt(3)-2

Toplamları -4

On Sunday, October 10, 2021 at 3:01:23 PM UTC+3 EXCALİBUR wrote:

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