Trigo
25 views
Skip to first unread message
Nihat Maliki
Apr 29, 2021, 3:39:28 AM4/29/21
to tm...@googlegroups.com
tan15*tan51*tan57*tan63 = ?
Teşekkür ederim
cems...@gmail.com
Apr 29, 2021, 4:52:20 PM4/29/21
to TMOZ
x=tan15*tan51*tan57*tan63
=tan15*tan51*tan(60-3)*tan(60+3)*tan3/tan3
=tan15*tan51*tan(3*3)/tan3
=tan15*tan51*tan9/tan3
=tan15*tan51*tan9*cot3
=sin15/cos15*cos3/sin3*tan51*tan9
=(sin15*cos3)/(cos15*sin3)*tan51*tan9
=[1/2*(sin18+sin12)]/[1/2*(sin18-sin12)]*tan51*tan9
=(sin18+sin12)/(sin18-sin12)*tan51*tan9
=(sin54-sin30+sin12)/(sin54-sin30-sin12)*tan51*tan9
=(2cos42*sin12+2cos60*sin12)/(2cos42*sin12-2cos60*sin12)*tan51*tan9
=[2sin12*(cos60+cos42)]/[2sin12*(cos42-cos60)*tan51*tan9
=(cos60+cos42)/(cos42-cos60)*tan51*tan9
=(2cos51*cos9)/(2sin51*sin9)*tan51*tan9
=cos51/sin51*cos9/sin9*tan51*tan9
=cot51*cot9*tan51*tan9
=1
=tan15*tan51*tan(60-3)*tan(60+3)*tan3/tan3
=tan15*tan51*tan(3*3)/tan3
=tan15*tan51*tan9/tan3
=tan15*tan51*tan9*cot3
=sin15/cos15*cos3/sin3*tan51*tan9
=(sin15*cos3)/(cos15*sin3)*tan51*tan9
=[1/2*(sin18+sin12)]/[1/2*(sin18-sin12)]*tan51*tan9
=(sin18+sin12)/(sin18-sin12)*tan51*tan9
=(sin54-sin30+sin12)/(sin54-sin30-sin12)*tan51*tan9
=(2cos42*sin12+2cos60*sin12)/(2cos42*sin12-2cos60*sin12)*tan51*tan9
=[2sin12*(cos60+cos42)]/[2sin12*(cos42-cos60)*tan51*tan9
=(cos60+cos42)/(cos42-cos60)*tan51*tan9
=(2cos51*cos9)/(2sin51*sin9)*tan51*tan9
=cos51/sin51*cos9/sin9*tan51*tan9
=cot51*cot9*tan51*tan9
=1
29 Nisan 2021 Perşembe tarihinde saat 10:39:28 UTC+3 itibarıyla nihadma...@gmail.com şunları yazdı:
tan15*tan51*tan57*tan63 = ?Teşekkür ederim
Reply all
Reply to author
Forward
0 new messages