Highlighting menu based on controller called - Symfony users (DISABLED)

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Message from discussion Highlighting menu based on controller called
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Date: Mon, 30 May 2011 00:20:46 -0600
Message-ID: <BANLkTikCK7k9S-pH+OCdEUMAnimzo_f...@mail.gmail.com>
Subject: Re: [symfony-users] Re: Highlighting menu based on controller called
From: oscar balladares <liebegr...@gmail.com>
To: symfony-users@googlegroups.com
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What I'm doing is to get the actual route in template, and if a route matchs
a category (lets say),
then print an "id='current'"

for example:

<li><a
         {% if app.request.attributes.get('_route') == 'homepage'  %}
         class='current'
         {% endif %}
       href="{{ path('homepage') }}">Home</a></li>

That's it. Of course it will become clumsy when you have many links cause it
is hard to read through.
I'll go with MenuBundle in my next project update schedule.

2011/5/28 FuzzyBird <nicolas.worm...@gmail.com>

> I think a good way to do it is, in the controller :
>
> // first generate the menu structure
>
>  // you may want to do the following in a loop for all your menu items
> if ($this->get('router')->generate('some-route') === $this-
> >get('request')->getRequestUri() ){
>      // highlight the link of this route
> }
>
> Hope it helped
>
> On May 12, 8:20 pm, Filipe La Ruina <filaru...@gmail.com> wrote:
> > Hey guys,
> > I've been searching for a way of getting the controller that was called
> so I
> > can highlight the menu.
> > I looked in the HTTP Foundation class and it seems that there is no way
> of
> > doing it.
> > Even searching here I couldn't find anyone that had the same problem.
> > Well, now i'm doing it the following way (note that I need it to show
> some
> > element in the html and a class in an element)
> >
> > <ul class="menu">
> >             <li {% if (app.request.getPathInfo  == '/foo')
> > %}class="selected"{% endif %}>
> >                 {% if (app.request.getPathInfo  == '/foo') %}
> >                 <span class="border left"></span>
> >                 {% endif %}
> >                 <a href="{{ url('foo') }}">Foo</a>
> >                 {% if (app.request.getPathInfo  == '/foo') %}
> >                 <span class="border right"></span>
> >                 {% endif %}
> >             </li>
> >             <li {% if (app.request.getPathInfo  == '/bar')
> > %}class="selected"{% endif %}>
> >                 {% if (app.request.getPathInfo  == '/bar') %}
> >                 <span class="border left"></span>
> >                 {% endif %}
> >                 <a href="{{ url('bar') }}">Bar</a>
> >                 {% if (app.request.getPathInfo  == '/bar') %}
> >                 <span class="border right"></span>
> >                 {% endif %}
> >             </li>
> > </ul>
> >
> > For now it is working since I don't have /foo/abc for example, all the
> urls
> > are /foo and /bar so the test will work.
> > Also I think that is not a nice way of testing (actually using the url
> and
> > not the controller name)
> > So is there anyway of getting the controller name on the template?
>
> --
> If you want to report a vulnerability issue on symfony, please send it to
> security at symfony-project.com
>
> You received this message because you are subscribed to the Google
> Groups "symfony users" group.
> To post to this group, send email to symfony-users@googlegroups.com
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>

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What I&#39;m doing is to get the actual route in template, and if a route m=
atchs a category (lets say),<div>then print an &quot;id=3D&#39;current&#39;=
&quot;</div><div><br></div><div>for example:</div><div><br></div><div><div>
&lt;li&gt;&lt;a</div><div>=A0=A0 =A0 =A0 =A0<span class=3D"Apple-tab-span" =
style=3D"white-space:pre">	</span>{% if app.request.attributes.get(&#39;_ro=
ute&#39;) =3D=3D &#39;homepage&#39; =A0%}</div><div>=A0=A0 =A0 =A0 =A0<span=
 class=3D"Apple-tab-span" style=3D"white-space:pre">	</span>class=3D&#39;cu=
rrent&#39;</div>
<div>=A0=A0 =A0 =A0 =A0<span class=3D"Apple-tab-span" style=3D"white-space:=
pre">	</span>{% endif %}</div><div>=A0=A0 =A0 =A0=A0href=3D&quot;{{ path(&#=
39;homepage&#39;) }}&quot;&gt;Home&lt;/a&gt;&lt;/li&gt;</div><div><br></div=
><div>That&#39;s it. Of course it will become clumsy when you have many lin=
ks cause it is hard to read through.</div>
<div>I&#39;ll go with MenuBundle in my next project update schedule.</div><=
br><div class=3D"gmail_quote">2011/5/28 FuzzyBird <span dir=3D"ltr">&lt;<a =
href=3D"mailto:nicolas.worm...@gmail.com">nicolas.worm...@gmail.com</a>&gt;=
</span><br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex;">I think a good way to do it is, in the cont=
roller :<br>
<br>
// first generate the menu structure<br>
<br>
=A0// you may want to do the following in a loop for all your menu items<br=
>
if ($this-&gt;get(&#39;router&#39;)-&gt;generate(&#39;some-route&#39;) =3D=
=3D=3D $this-<br>
&gt;get(&#39;request&#39;)-&gt;getRequestUri() ){<br>
 =A0 =A0 =A0// highlight the link of this route<br>
}<br>
<br>
Hope it helped<br>
<div><div></div><div class=3D"h5"><br>
On May 12, 8:20=A0pm, Filipe La Ruina &lt;<a href=3D"mailto:filaru...@gmail=
.com">filaru...@gmail.com</a>&gt; wrote:<br>
&gt; Hey guys,<br>
&gt; I&#39;ve been searching for a way of getting the controller that was c=
alled so I<br>
&gt; can highlight the menu.<br>
&gt; I looked in the HTTP Foundation class and it seems that there is no wa=
y of<br>
&gt; doing it.<br>
&gt; Even searching here I couldn&#39;t find anyone that had the same probl=
em.<br>
&gt; Well, now i&#39;m doing it the following way (note that I need it to s=
how some<br>
&gt; element in the html and a class in an element)<br>
&gt;<br>
&gt; &lt;ul class=3D&quot;menu&quot;&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 &lt;li {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/foo&#39;)<br>
&gt; %}class=3D&quot;selected&quot;{% endif %}&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/foo&#39;) %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;span class=3D&quot;border left&quo=
t;&gt;&lt;/span&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% endif %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;a href=3D&quot;{{ url(&#39;foo&#39=
;) }}&quot;&gt;Foo&lt;/a&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/foo&#39;) %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;span class=3D&quot;border right&qu=
ot;&gt;&lt;/span&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% endif %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 &lt;/li&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 &lt;li {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/bar&#39;)<br>
&gt; %}class=3D&quot;selected&quot;{% endif %}&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/bar&#39;) %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;span class=3D&quot;border left&quo=
t;&gt;&lt;/span&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% endif %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;a href=3D&quot;{{ url(&#39;bar&#39=
;) }}&quot;&gt;Bar&lt;/a&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% if (app.request.getPathInfo =A0=3D=
=3D &#39;/bar&#39;) %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 &lt;span class=3D&quot;border right&qu=
ot;&gt;&lt;/span&gt;<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 {% endif %}<br>
&gt; =A0 =A0 =A0 =A0 =A0 =A0 &lt;/li&gt;<br>
&gt; &lt;/ul&gt;<br>
&gt;<br>
&gt; For now it is working since I don&#39;t have /foo/abc for example, all=
 the urls<br>
&gt; are /foo and /bar so the test will work.<br>
&gt; Also I think that is not a nice way of testing (actually using the url=
 and<br>
&gt; not the controller name)<br>
&gt; So is there anyway of getting the controller name on the template?<br>
<br>
--<br>
If you want to report a vulnerability issue on symfony, please send it to s=
ecurity at <a href=3D"http://symfony-project.com" target=3D"_blank">symfony=
-project.com</a><br>
<br>
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</div></div></blockquote></div><br></div>

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