Having problems with multiple flashvars in wordpress

chieffan

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Nov 17, 2009, 4:27:52 PM11/17/09

to SWFObject

I have searched on here and it seems what I am doing is right, but
it's not working.

In the header.php of my Wordpress site, in the <head> section, I have
something like this after my call of the swfobject:

<script type="text/javascript">

var flashvars = {};
flashvars.level = "<?php ;echo $level;?>";
flashvars.score = "<?php echo $score;?>";
swfobject.embedSWF("mydomain/externalflash.swf", "externalflash",
"760", "360", "9.0.0","expressInstall.swf",flashvars);

</script>

<script type="text/javascript">

var flashvars2 = {};
flashvars.level2 = "<?php ;echo $level2;?>";
flashvars.score2 = "<?php echo $score1;?>";
swfobject.embedSWF("mydomain/externalflash2.swf", "externalflash2",
"760", "360", "9.0.0","expressInstall.swf",flashvars2);

</script>

My problem is the second swf shows but the flash vars dont pass. I
have put the number 2 next to the flashvars and tried without. It
only displays the movie without the data.

I am using swfobject 2 on this. Anyone have any suggestions?

In Wordpress, I then call it via <div id="externalflash2">alternate
content</div>

Any ideas?

Thanks.

Sam Sherlock

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Nov 17, 2009, 5:14:51 PM11/17/09

to swfo...@googlegroups.com

in the following I am declaring a single var for flashvars and reseting it between calls to embedswf

var flashvars = {};
flashvars.level = "<?php ;echo $level;?>";
flashvars.score = "<?php echo $score;?>";
swfobject.embedSWF("mydomain/externalflash.swf", "externalflash",
"760", "360", "9.0.0","expressInstall.swf",flashvars);

flashvars = {};

flashvars.level2 = "<?php ;echo $level2;?>";
flashvars.score2 = "<?php echo $score1;?>";
swfobject.embedSWF("mydomain/externalflash2.swf", "externalflash2",

"760", "360", "9.0.0","expressInstall.swf",flashvars);

</script>
- S

Aran Rhee

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Nov 17, 2009, 5:52:23 PM11/17/09

to swfo...@googlegroups.com

Have a santiy check of your code on the 2nd flashvars object:

var flashvars2 = {};

flashvars.level2 = "<?php ;echo $level2;?>";
flashvars.score2 = "<?php echo $score1;?>";

You are creating "flashvars2", then adding two variables to a different (the original) "flashvars" object :)

BTW, you don't need separate <script> tags between your declarations.

Aran

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chieffan

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Nov 18, 2009, 9:49:14 AM11/18/09

to SWFObject

I figured out my problem.

I was also adding the number of the Flash Var to the passing value

var flashvars2 = {};
flashvars.level2 = "<?php ;echo $level2;?>";

so it should have been

var flashvars2 = {};
flashvars.level = "<?php ;echo $level2;?>";

Thanks for the help.

Sam Sherlock

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Nov 18, 2009, 9:51:34 AM11/18/09

to swfo...@googlegroups.com

then this is not being used

var flashvars2 = {};

- S

2009/11/18 chieffan <rodand...@gmail.com>

Aran Rhee

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Nov 18, 2009, 5:06:27 PM11/18/09

to swfo...@googlegroups.com

Review #2 - you want:

var flashvars2 = {};

flashvars2.level = "<?php ;echo $level2;?>";

Aran

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