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Understanding Confidence Intervals. Please comment.

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Bacle

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Nov 9, 2009, 2:30:00 AM11/9/09
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Could someone please tell me if I am understanding confidence intervals correctly.?. Here is a problem I
am trying to answer.( I will mark my answers with a ------- to make it easier to recognize. Please feel free to check just one-or-two of the answers if this seems too long). I would appreciate your comments:


Here is the problem:

Teachers
Software analysis of the salaries of a random sample of 288 Nevada teachers produced the confidence interval shown below. Which conclusion is correct? What's wrong with the others?

t-Interval for m: with 90.00% Confidence, 38944 < m(TchPay) < 42893


a)If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce this confidence interval.

---------------------------------------------------
a)False: the confidence interval would depend on the value of sampling mean. Since we are using t-intervals, we must be using the sample error, which makes intervals even more variable than if we knew the true pop. standard deviation.

All we can say is that there is a 95% probability that
the true average salary lies in a 95% confidence interval, whatever interval we construct.


________________________________________________


b)If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce a confidence interval that contained the mean salary of all Nevada teachers.

-----------------------------------------------
True, if we constructed 95% confidence t-intervals with the sampling data given.


____________________________________________________

c)About 9 out of 10 Nevada teachers earn between $38,944 and $42,893.

------------------------------------------------------

False. The confidence interval is about the true population mean, about the probability that the true mean lies in the interval, not about the probability that a teacher earns an amount in this range.


_________________________________________________________

d)About 9 out of 10 of the teachers surveyed earn between $38,944 and $42,893.
------------------------------------------------------

False.


_____________________________________________________

d)We are 90% confident that the average teacher salary in the United States is between $38,944 and $42,893.

-------------------------------------------------

d)True. This is the actual meaning of a confidence interval.


Thanks For Any Comments.

Rich Ulrich

unread,
Nov 9, 2009, 3:20:49 PM11/9/09
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On Mon, 09 Nov 2009 02:30:00 EST, Bacle <ba...@yahoo.com> wrote:

>Could someone please tell me if I am understanding confidence intervals correctly.?. Here is a problem I
>am trying to answer.( I will mark my answers with a ------- to make it easier to recognize. Please feel free to check just one-or-two of the answers if this seems too long). I would appreciate your comments:
>
>
>Here is the problem:
>
> Teachers
>Software analysis of the salaries of a random sample of 288 Nevada teachers produced the confidence interval shown below. Which conclusion is correct? What's wrong with the others?
>
>t-Interval for m: with 90.00% Confidence, 38944 < m(TchPay) < 42893
>
>
>a)If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce this confidence interval.

That is not a "conclusion." That is an erroneous statement of
a definition.

>
>---------------------------------------------------
>a)False: the confidence interval would depend on the value of sampling mean. Since we are using t-intervals, we must be using the sample error, which makes intervals even more variable than if we knew the true pop. standard deviation.
>
> All we can say is that there is a 95% probability that
> the true average salary lies in a 95% confidence interval, whatever interval we construct.

Not too bad. Except that the original was "90%" and not 95%.

>________________________________________________
>
>
>b)If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce a confidence interval that contained the mean salary of all Nevada teachers.

Again, that is a definition, not a "conclusion."


>
>-----------------------------------------------
> True, if we constructed 95% confidence t-intervals with the sampling data given.

Again, 95 is not 90.


>____________________________________________________
>
>c)About 9 out of 10 Nevada teachers earn between $38,944 and $42,893.
>
>------------------------------------------------------
>
>False. The confidence interval is about the true population mean, about the probability that the true mean lies in the interval, not about the probability that a teacher earns an amount in this range.
>
>_________________________________________________________
>
>d)About 9 out of 10 of the teachers surveyed earn between $38,944 and $42,893.
>------------------------------------------------------
>
>False.
>_____________________________________________________
>
>d)We are 90% confident that the average teacher salary in the United States is between $38,944 and $42,893.

We don't freely extrapolate from "Nevada" to "the United States."


>
>-------------------------------------------------
>
>d)True. This is the actual meaning of a confidence interval.

The definition that you gave in response to (a) is a better
defintion. "90% confident" is an awkward expression
whose meaning would never be guessed by someone who
doesn't know the conventional answer.

--
Rich Ulrich

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