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Newsgroups: sci.physics.research
From: "nightlight" <nightli...@omegapoint.com>
Date: Sat, 10 Sep 2005 15:09:25 +0000 (UTC)
Local: Sat, Sep 10 2005 11:09 am
Subject: Re: photoelectric effect : hypothetical experiment
> I said a single photon and a freq =f such that work function = hf. Single photon has infinite extent in time and space. They are thus unsuitable for coincidence measurements (which you would need to establish whether there is any additional/nonclassical anticorrelation or exclusivity in the counts/ionisations on the two plates). An easy way to see the problem is to consider Heinseberg uncertainty relation for the single photon f states. The time-energy uncertainty relations dE*dt >= h/2 imply that for fixed frequency photon (dE=0) you will have dT=infinity, making any timestamping of ionization events meaningless. The states with minimum uncertainty (with the equality: dE*dt = h/2) correspond to the coherent states of EM field, which are perfectly classical states (for coherent states the photon number observable has Poissonian distribution of photocounts, which is what classical EM predicts as well). More generally, the sharp photon number states (which are a basis within the sharp energy eigen-subspaces) cannot be used for Quantum Optical coincidence measurement due to dT=infinity, and the optimum coincidence measurements (the minimum uncertainty) are obtained for coherent states, thus their counts correlations will be classical. Note also that the coherent states can approach limit dE=0 with You must Sign in before you can post messages.
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