Newsgroups: sci.physics.relativity
From: "Ken S. Tucker" <dynam...@vianet.on.ca>
Date: 28 Apr 2005 12:37:47 -0700
Local: Thurs, Apr 28 2005 3:37 pm
Subject: Theory of Relativity
In this post, it's my intention to show the
extraordinary beauty and simplicity I find in the Theory of Relativity. It employs the ingenious logic developed by mathematicians called tensor analysis. The fundamental assumption of relativity is Beginning with the well known ds^2 = g_uv dx^u dx^v , u,v,w={0,1,2,3}. We can use association provided the covariant g_uv;w = 0. Then by association, ds^2 = dx_u dx^u. Expanding to time and space gives, ds^2 = dx_0 dx^0 + dx_i dx^i , i,j={1,2,3}. The absolute spatial motion I'll define by dx_i dx^i = Absolute spatial motion. Absolute spatial motion cannot exist, IOW's dx_i dx^i =0. However, relative spatial motion cannot vanish, dx_i =0 always, to insure dx_i dx^i=0 always, and is the mathematical description of the U_i = dx_i/ds =0. By using tensor algebra we obtain from that, g_0i = - g_ij dx^j/dx^0, and generally, ds^2 = g_00 dx^0 dx^0 - g_ij dx^i dx^j , (always). For an SR application, sub the metric values, g_00 = g_11 = g_22 = g_33 =1, g_ij =0 when i =/= j and g_0i = -dx^i/dx^0, and find by algebra, ds^2 = g_00 dx^0 dx^0 - g_ij dx^i dx^j == dt^2 - dx^2 - dy^2 - dz^2. The succinct U_i=0 provides Minkowski spacetime, Moving to General Relativity, the following absolute DU_i = U_i;w dx^w =0 . Using association, U_i = g_iu U^u =0 therefore, DU_i = g_iu DU^u =0 and thus, DU^u =0, aka the geodesic equation. We have arrived at the equation for the geodesic The g_uv;w=0 is the mathematical expression for The geodesic equation is expanded to, DU^u/ds = dU^u/ds + GAMMA^u_ab U^a U^b = 0 (ref, see Weinberg's Eq. (5.1.7)), and is the equation of Up to this point we've used two assumptions 1) U_i=0 2) g_uv;w=0 where (1) is a statement of the law of Relativity that excludes I use (1) and (2) in relativity mathematics, is there a reason not to? TIA You must Sign in before you can post messages.
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