Gmail Calendar Documents Reader Web more »
Recently Visited Groups | Help | Sign in
Google Groups Home
Message from discussion Why are the 'Fixed Stars' so FIXED?
The group you are posting to is a Usenet group. Messages posted to this group will make your email address visible to anyone on the Internet.
Your reply message has not been sent.
Your post was successful
 
From:
To:
Cc:
Followup To:
Add Cc | Add Followup-to | Edit Subject
Subject:
Validation:
For verification purposes please type the characters you see in the picture below or the numbers you hear by clicking the accessibility icon. Listen and type the numbers you hear
 
Henri Wilson  
View profile  
 More options May 3 2007, 7:35 pm
Newsgroups: sci.physics.relativity, sci.astro
From: HW@....(Henri Wilson)
Date: Thu, 03 May 2007 23:35:42 GMT
Local: Thurs, May 3 2007 7:35 pm
Subject: Re: Why are the 'Fixed Stars' so FIXED?
On 3 May 2007 02:58:34 -0700, George Dishman <geo...@briar.demon.co.uk> wrote:

>I posted this yesterday through google but it seems to
>have vanished. Luckily I saved a copy first, apologies
>for the duplication if the original eventually turns up.
>> >> George, you are still insisting that the wavelength changes in the observed
>> >> light will be of the same proportion as the brightness variation...

>> >They are one and the same mechanism Henry.

>> George, I gave you the analogy of a rubber ball sinking in water.

>You can give me an analogy of an elephant up an orange tree, it
>means nothing. Physics is mathematical Henry so the equation
>defines what happens and analogies are only useful as an aid to
>understing. If the analogy doesn't reflect the equation, it is just
>misleading. Forget analogies, just apply your "c+v" equation.

I have George...
You refuse to listen.
There are plenty of instances where the BaTh does NOT require continued
ballistic movement. I gave you another analogy where there is continued but
reduced movement.
You are assuming the ends of a photon are completely independent of each other.
The very fact that an individual photon can exist means that it must have some
kind of identifying property and 'structure' that distinguishes it from
'nothing'. There is absolutely no reasn to assume the ends will continue to
move in way pulsar pulses appear to.

>> >> a tenfold
>> >> increase in brightness would also mean a doppler shift corresponding with 10c
>> >> !!!!!...if the VDoppler equation was used.

>> >That's why your claims are nonsense.

>> How can you brush them off as nonsense ...

>Consider the grating question as it would relate to a simple RF
>signal.

>Wavefronts approach a series of wires (the asterisks are the wires
>seen
>along their length.

>  _____________________________
>  _____________   _____________
>  _____________ | _____________
>  _____________ | _____________
>  _____________ v _____________
>  _____________________________
>  _____________________________
>  _____________________________

>  *   *   *   *   *   *   *   *

>The field induces current in the wires which then re-radiate. That
>raiation should be isotropic in a plane perpendicular to the axis
>of the wires but interferences creates 'lobes' or preferred
>directions.
>There is a peak of radiation at any angle (which depends on the
>frequency or wavelength) where the waves arrive in phase. The
>reflected wavefronts might go like this:

>                           \ \
>                        \ \ \ \
>                         \ \ \ \
>                          \ \ \ \
>                           \ \ \ \
>                            \ \ \ \
>                             \ \ \ \
>                              \ \ \
>                               \
>  *   *   *   *   *   *   *   *

>Changing the scale so the horizontal line is the grating, the
>signal arriving vertically downwards is reflected at some angle
>like this and the maximum field, say measured with a dipole
>and oscilloscope as mentioned in my other post, might have
>a maximum at 'A'. What you are telling me is that TDoppler
>affects the waves at a macrosopic level hence the angle to
>A but that if we think of that wave as bing delivered in small
>bursts, each burst of classical waves (which you are calling
>a photon) is affected by an amount which is smaller by the
>factor K so the bursts all get deposited at location B.

>    |
>    |  \A
>    |  /\
>    | /  \B
>  __|/_   \

>You can't have all the "photons" arriving at B and the energy
>appearing at A.

The question you want me to answer is, "how is an individual photon affected by
being in a group of photons?"

I doubt if anyone can give you a decent answer to that....but like I said
before, I doubt if individual photons making up an RF signal would be
diffracted in the same way as the macroscopic wave itself.

>> when they fit the data? That's not a
>> very scientific attitude George.

>The first rule of a scientific attitude is slf-consitency. Your
>nonsense
>predicts two contradictory locations for the light reflected from a
>grating, that's why I dismiss it as nonsense.

You have twisted the meaning of what I am saying...and since there is no
evidence either way, you don't have a leg to stand on.

>> >> I have now explained why that is not true.

>> >> Fractional Photon Length Change = (Bunching Factor)/K
>> >> ...where K can be large.

>> >Nope, K=1 and it applies to the _observed_ Doppler shift equation
>> >as well as the luminosity. What that means is that a very small
>> >_actual_ speed can produce a very large luminosity variation but
>> >the observed frequency would be changed so much the star
>> >would _appear_ to be moving at 10c above.

>> ....and it doesn't happen like that ...

>Right, so the variation must be intrinsic.

No George.
I have explained. I will not do it again.

>> >You are the only one confused Henry, BaTh is very simple. It
>> >says both luminosity and Doppler shift are due to to TDoppler,
>> >and if K > 1 then both get changed. The relationship between
>> >the two is unaffected by K.

>> ...but that doesn't fit the data George...

>Yes it does Henry, Cepheid variations are intrinsic to the star.

>> Your classical wave theory doesn't apply to individual photons nor does your
>> 'ballistic shrinkage'.

>Your so-called "photons" are nothing more than bursts of classical
>waves, the view Planck held in 1914, and a purely classical analysis
>is entirely valid.

Nobody knows anything about the particle nature of a photon George, so don't
try to make out they do. It is clearly not just a 'classical wave'. It is a
package of energy with definite properties and structure.

>> >Wrong again henry, when will you learn. BaTh says it is TDoppler
>> >that matters.

>> Of course,...

>Good, try to remember that, you keep making the same error
>and I'm fed up correcting it. My point regarding a Fouier analysis
>stands.

The VDoppler component is generally negligible. Forget it...

>> There is the source of your mistake. It's simple....You are regarding the
>> origin of a single photon as being the same as the origin of a stream of
>> bullets...
>> That's quite ridiclulous George. You are taking the Ballistic theory too far.

>I am applying ballistic theory precisely, it says every (part of
>every) wave
>of a signal moves at c+v where v is the instantaneous speed when that
>(part of the) wave was emitted. the rest is simple mathematical
>derivation.
>That means TDoppler is c(c+v)/(c^2-da) and if you then quantise that
>received frequency into small packets of energy, each packet behaves
>as
>if it had that same frequency. It must do Henry, the individual wave
>bursts
>cannot be deflected by a grating at an angle different from the bulk
>wave.

It is the wave formed by the group of photons that is diffracted.
If you are considering monochromatic light, naturally all photons will be
diffracted to the same angle.

>> You know the lengths of the cars don't change when they bank up on a slow
>> section of the highway...and bullets don't change length when fired from an
>> accelerating gun.

>If you want to use those for an analogy that accurately reflects the "c
>+v"
>equation, each car or bullet is but a point on the wave within the
>long train
>of waves that you call a photon. It's easier to think of them
>representing
>peaks of the sine wave but any other part is equally valid.

When water waves are diffracted, it is a macroscopic effect, not a molecular
one.
if you could 'diffract' the line of cars on the highway, you would get two
different angles. One being due to the 'wavelength' defined by the distance
between cars and the other but the lengths of the cars themselves.

I suppose you would get another angle from the fact that the wheels were all
the ame diameter.

>> >The rest is intrinsic.
>> >That interpretation matches all you have discovered from
>> >pulsars and EF Dra and there is no evidence to question it.

>> I gave you MY light curve for EF Dra. It fits an ADoppler type prediction..

>No, the one that fitted was an error using half the period (I'm
>inclined to
>give you the benefit of the doubt and think it wasn't deliberate
>fraud) but
>the phase is actually 90 degrees out from ADoppler, it matches
>VDoppler.

Not in my diagram. The brightness peak, which is eclipsed, occurs when the star
is on the LOS, furthest away...That is where maximum ADoppler occurs. Do you
not agree George? So the BaTh wins again.

>> >> When converted to orbit speeds, via VDoppler math, the velocities are those we
>> >> normally see in published cuves.

>> >> The truth is, the observed wavelength shifts are all ADoppler derived

>> >Nope, your analysis has shown they are VDoppler.

>> For pulsars, maybe...but that's what we would expect because we are dealing
>> with groups of photons..

>And for the contact binaries too, and you will find exactly the same
>for all eclipsing binaries.

The BaTh has now clearly won that argument.

>> >> >Wrong way round Henry, the observations are always in
>> >> >phase with the VDoppler curve and 90 degrees out from
>> >> >the ADoppler in those we have looked at.

>> >> Not so George.

>> >Yes Hewnry, go back and check your own calculations, I'm not
>> >telling you anything you haven't already worked out for yourself.

>> I have checked everything George

>Then you made the same mistake twice, the curve for EF Dra is
>90 degrees out from ADoppler.

The BaTh has now clearly won that argument.

>> and it now all fits together.
>> The BaTh is complete.

>> >> The ADoppler shifts are always (or nearly) in phase with the
>> >> brightness curves.

>> >but 90 degrees out from the orbital phase, the curves are VDoppler.

>> No George,

>Yes Henry, the peak of the velocity curve is half way between
>the eclipses, not coincident with them.

No George, have another look at: www.users.bigpond.com/hewn/efdrag.jpg

The peak velocity curve is in phase with the peak brightness curve, which in in
phase with hte eclipses.

>> the ADoppler curves are virtually the same as the brightness
>> curves...but much smaller in amplitude.

>You are forgetting the brightness curves vary at twice the rate
>of the orbital period and velocity curves, they don't even have
>the same frequency, never mmind phase.

I have projected the brighness curve of one star in hte diagram. All the phases
match ADoppler.
The BaTh has won EF Dra.

>> >No, your original assumed they moved at c, it was just a screw up,
>> >but that's not what we are discussing.

>> See.,.. you don't even know what the red curve was.
>> it showed the positions of INCOMPRESSIBLE photons moving at c+v....in relation
>> to their emission phase.

>Nope, incompressible photons would have NO Doppler whatsoever.

That's what is assumed. ..but their relative positions move with 'bunching'.

>It assumed either that photons were both FULLY compressible for
>differences in speed due to acceleration resulting from speed
>equalisation and at the same time totally INCOMPRESSIBLE
>for differences in speed due to acceleration of the source or that
>the photons moved at c. Whatever your thinking, if you aggregate
>a group of such self-contradictory beasties such that they form
>a modulated wave, the modulation (hence the energy carried by
>the wave) travels at c regardless of the speed of the source.

>Just do the maths Henry, you can find all this out for yourself.

I have explained this many times.

>> >> This is definitel not classical wave theory. This is a completely new Wilsonian
>> >> breakthrough!

>> >Sorry Henry, it is still purely classical and based on waves.

>> The cars don't shrink George.

>They represent individual waves within your classical "photons"
>Henry, and they bunch up and spread apart depending on speed
>difference.

They don't shrink. The spacing does.

>> >Ballistic IS classical, you don't get more classical than a cannon
>> >ball !

>> ...and the ball doesn't shrink when fired from a rocking boat.

>The bullets in Jeff Root's animation bunch and spread just like
>the waves in your classical photon wave trains. I thought you
>understood that back when he drew it. (Jim never did.)

The bullets themselves don't change length George.

>> It doesn't mean that at all.
>> If you are thinking about something like an RF signal, its 'frequency' refers
>> to the way a great many photons interact to create a traveling wave. It is
>> probably a 'photon density' distribution. The 'frequency' is just the rate at
>> which the 'wavecrests' arrive. It has nothing to do with the intrinsic
>> properties of individual photons.

>The energy carried by the wave goes where the photons go and vice
>versa, they can't land in different places.

Explained above...

>> I think we can assume there is energy in the wave as well as in the individual
>> photons.

>The wave has no existence other than as a term meaning the aggregate
>of the individuals.

Bull....explained above.

>> if it signifies TWO eclipses, you would expect the brightness to be constant
>> between eclipses. That is not what is observed.

>It is an _overcontact_ binary, look at the diagram I cited. The
>observed curve is almost an exact fit to that predicted by the
>Roche lobe model.

>>  The EF Dra interpretation is
>> completely wrong...

>What a coincidence that it fits the prediction then. You are just
>raving Henry.

The BaTh has convincingly won EF Dra...and presumably all other contact
binaries.

>> >> It so happens that the VDoppler velocity curve shape and the ADoppler one are
>> >> virtually the same for certain values of eccentricity and yaw angle.

>> >The phase is not the same, that's how we tell them apart.

>> It is....

>Nope, 90 degrees out.

Nope George.
Have another look at:  www.users.bigpond.com/hewn/efdrag/jpg

The phase is correct fro ADoppler.

>> >> The answer should be pretty obvious anyway.

>> >You must be joking! It's horribly hard. You need to get
>> >the equatioins for the Roche lobes, consider the
>> >equations for limb darkening, consider mutual heating
>> >and thermal mixing and then turn all that into general
>> >equations for harmonic content. I wouldn't even try,
>> >but if you think you can, go ahead.

>> How about throwing away all old astronomy theories, burning all the books and
>> starting afresh with BaTh.

>How about starting again with phlogiston, it has as much chance
>of being right as BaTh. Whatever you start with, as soon as you
>look at actual experiments, you are force to the conclusion that
>the universe is locally Lorentz invariant.

The BaTh has won the contact binary argument....

>> >Sure, if BaTh was right. However it would vary in phase with
>> >VDoppler if the extinction distance was small and ADoppler
>> >if it is large. Your challenge is to prove using actual observation
>> >that we see ADoppler, not VDoppler. So far EF Dra and the
>> >pulsars all show VDoppler only, no hint of ADoppler. Henry,
>> >ADoppler doesn't exist - ever.

>> George, here's another way to look at this.

>> Let's assume a photon emission occurs over a fixed time interval. Also assume
>> that what is emitted is a package of energy in the form of an EM wave. For a
>> particular energy level transition, the wave has a fixed number (N) of
>> 'wavelengths' or cycles.  This matches E = h.nu.

>OK.

>> Let the package be emitted at speed c relative to the source.

>Don't skip the detail, as each wave of the packet is emitted, it
>is launched at c+v where v is the speed at that moment.

>> For an inertial source, the length of the photon is c/N. ...but for an
>> accelerating source, it is something different, the variation being a function
>> of a, not v.

>Right,  Different waves in the packet therfore get different speeds
>and the usual c+v bunching factor due to acceleration applies.

Initially that may be true...but I'm suggesting any such differences are
quickly dampened out and the photon settles down to a length that reflects its
average emission ACCELERATION.

>> This would suggest that photon 'shrinkage' occurs only at origin time....AND IT
>> IS ACCELERATION DEPENDENT.

>No, that contradicts what you just said.

Well it could go on for a little time after emission.

>> If you want to introduce ballistics, you can to some extent..... but make sure
>> the effect is dampened out long before it is in the case of movement between
>> pulsar pulses.

>Right, the damping happens as a decresing exponential over
>some distance, you think light days, I think less, but w agree
>on the overall characteristic of the behaviour.

But we don't agree that the rate within a photon is far greater than the rate
BETWEEN photons.

>> >> For my purposes, the cepheid doesn't need a second body.

>> >Ah , so you have given that up then. Fine.

>> Not entirely. The oscillations could be related to the orbiting of a large
>> second body. ..after all the constancy of cepheid periods strongly suggests
>> some kind of connection with an orbit.

>No, Cepheid variation is less stable.

So are many orbit periods.

>> >> Its huffing is
>> >> analogous to orbiting eccentrically as far as radial velocity is concerned.
>> >> The BaTh DOES however provide a perfectly sound and accurate expanation for the
>> >> brightness variation, something no other theory can do.

>> >Rubbish, plasma theory shows how the opacity changes and
>> >thermodynamics, radiation pressure and ordinary dynamics
>> >(momentum) does the rest.

>> Well, I haven't found paper yet where the author claim to have found a
>> convincing link between huffing and brightness.

>You would be better to look in a textbook.

Burn it.....

>> >A photomultiplier produces a flash for each photon, you should know
>> >that. The basic physics is the photoelectric effect. An electron
>> >ejected
>> >by a photon creates a cascade that generates enough light on the
>> >final phosphor to be measured.

>> A very sensitive PM might pick up single photons.

>All PMs pick up single photons, that's their job!

Their main job is to amplify very weak light signals. A single photon could
barely be seen above the noise.

>> What do you think might happen when you send an RF signal through a PM George?
>> :) :)

>Same thing, EM is EM, but the energy per photon is going to be very
>low so you would need a detector with much better sensitivity than
>is currently available.

Yep.

>> >> That's OK.
>> >> Perfectly in accord with hte P.E. effect.

>> >Of course, but it requires that the "wavelength" of a single photon
>> >is the same as the macroscopic wave of which it is a part, hence
>> >K=1.

>> Bull....

>> Plain bull!!!!

>Required for self-consistency Henry, see the grating discussion above.

Not required at all. Explained above...

>> I just provided a perfectly plausible mechanism that explains ADoppler photon
>> shrinkage. Think about it...

>Nothing you have said on this topic is plausible in theslightest, it
>is self-contradictory from the start.

You want it to be.....

>> >See the powerpoint presentation I citred where the explanation is
>> >laid
>> >out as an overview. denying reality doesn't make it go away.

>> I prefer ..

>I don't care what you prefer, you can't say something doen't exist
>when I gave you a presentation on it.

>> to accept the BaTh explanation. It works for most stars.

>It han't worked for any yet.

It has won cepheids, now it has also won contact binaries....

>> >> >So was I. You haven't applied your current classical BaTh to
>> >> >a grating so there are NO "grating equations" to have a speed
>> >> >term or not.

>> >> There is 'frequency of wavecrest arrival'.

>> >Yes, so? What is the BaTh equation?

>> One must make assumptions about the speed after reflection/transmission.

>Yes, so? What is the BaTh equation?

I don't knw....How long does the contact last?

>> I'm happy at this stage just to match brightness and velocity curves.

>You can match the velocity curves and they are VDoppler dominated,
>but you cannot match the luminosity curves without speeds greater
>than c.

 www.users.bigpond.com/hewn/efdrag/jpg......  The BaTh wins....

>> If you want to deviate into other areas, I'm sure you will soon find the BaTh
>> connection.

>> >> The bunching part is...but the photon shrinkage is more a mechanical effect.

>> >You are still treating a photon as an extended burst of classical
>> >waves though.

>> It is a package of energy stored as some kind of oscillation over an absolute
>> length. As shownabove, that length is 'source acceleration' dependent..

>> >> >No dominant, ADoppler < VDoppler * 1% in all cases so far.

>> >> VDoppler can't match brightness curves...not even to 0.01%.

>> >Correct.

>> >> VDoppler is
>> >> negligible.

>> >Wrong, you proved it is dominant therefore the luminosity variation
>> >must be intrinsic.

>> I have providid a theory that shows why photon length (and therrefore
>> 'frequency') is ADoppler dependent.

>No, you have plucked an equation out of thin air and tried to
>bolt it into your theory but the result is self contradictory. The
>equation c+v gives you the photon bunching factor already so
>any other additions to the theory will always break it.

It is not contradictory and it matches observation.
That's a step in the right direction....

>> >Not at all Henry, that's what I have been telling you and you keep
>> >denying, saying it depends not on the average but on da/dt which
>> >is crap.

>> It is not crap. It should be pretty obvious...almost trivial....

>It is crap, da/dt is not the average acceleration.

Yes it has to be integrated, naturally....

>> Something emitted over a long 'time length' should contract (spatially)
>> differently from something emitted over a 'short time length'....if the source
>> is accelerating.

>> get it now?

>Sorry Henry, you painted yourself into a corner and word salad won't
>get you out. If you mean photons have a varying bunching factor along
>the wavetrain if da/dt is non-zero, then I agree, and it is just
>another
>problem for BaTh.

The BaTh has already won....

>> I'm merely extending what you pointed out weeks ago when you detailed why the
>> width of a pulsar pulse should compress in the same proportion as the gap
>> bertween pulses. That clearly applies only to conditions of constant
>> acceleration.

>That's true, but you just stated it completely wrongly.

I didn't...

>> No we haven't agreed on that for INDIVIDUAL PHOTONS.

>Your photons are just trains of waves, at least 1000 for the sodium
>example I gave and much more if you do a proper classical analysis.

You don't know anything about the particle properties of photons.

>> >> The important point is that its length change is proportional to the difference
>> >> in emission speeds of its ends...that is an ADoppler change.

>> >It is also the mechanism behind VDoppler change which converts the
>> >variable speed/absolute wavelength at emission into the variable
>> >wavelength common speed we see.

>> I have provided an explanation of ADoppler photon compression.

>Self-contradictory handwaving.

But it works...

>> >> My program already includes random distribution of molecular velocities for
>> >> diffrent temperatures. It's prety rough but provides an indication of what to
>> >> expect.

>> >I asked about molecular accelerations, not velocities. You keep
>> >telling me VDoppler is negligible.

>> They are effectively included in the blue curve.

>Nope, the result would be an extreme broadening of spectral lines
>which isn't displayed in any way.

Most is unified before it leaves the star's influence.

>> >> That equation applies to pulses but not to individual photons.
>> >> You need the factor K.

>> >You can include the factor K if you want but it will apply
>> >to pulses too, use a fourier transform.

>> I don't need any fourier transform to see what's going on George.

>Yes you do, your handwaving is self-contradictory because you
>don't know how to derive photon behaviour from c+v so you think
>you can pluck an equation out of thin air. It doesn't work.

It matches the data.

>> >You seem to have a problem following this. If BaTh says the
>> >wavelength is unchanged then the angle shouldn't change.
>> >Since the angle does change, BaTh is falsified. That's your
>> >problem not mine. I have tried to give you a way out but you
>> >seem intent on proving BaTh wrong so I give up, you win,
>> >ballistic theory has been falsified.

>> George, YOU are the one with the problem.

>I'm not the one using BaTh.

>> The BaTh says the 'frequency' changes and therefore a doppler shift IS
>> observed.
>> YOUR theory says the wavelength is unaffected by grating movement and therefore
>> the angles should be the same for the moving grating.
>> Clearly, SR is falsified.

>The SR equations match the observed change of angle so SR
>is confirmed. BaTh on the other hand has to make a specific
>ad hoc assumption about the reflected speed in order to avoid
>being falsified. Post your BaTh equation - if you can ever work
>it out that is.

I told you what it is...

>> >> De Sitter was te crank.

>> >He was correct. If he had been wrong you wopuldn't need speed
>> >equalisation.

>> He was wrong for the same reason. He didn't consider speed equalization.

>Speed equalization wasn't part of the theory he was commenting
>on so he was right. AFAIK that bodge was added after he was dead
>so he didn't comment on it at all.

Extinction refuted his arguments. I would also add that he probably used
grossly inflated velocity figures, based on VDoppler instead of ADoppler.

www.users.bigpond.com/hewn/index.htm

Einstein's Relativity - the greatest HOAX since jesus christ's virgin mother.


    Reply to author    Forward  
You must Sign in before you can post messages.
To post a message you must first join this group.
Please update your nickname on the subscription settings page before posting.
You do not have the permission required to post.

Create a group - Google Groups - Google Home - Terms of Service - Privacy Policy
©2009 Google